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3 years ago

A cabin has room for seven campers and two counselors. How many cabins are needed for a total of 49 campers and 14 counselors?

Mathematics

2 answers:

navik [9.2K]3 years ago

7 0

7 cabins are needed.

adelina 88 [10]3 years ago

5 0

The answer is 7 because each camper holds 7 campers and 2 so there for 7 times 7 is 49 and 7 times 2 is 14

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2 years ago

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Transform the equation to isolate x: ax = bx 1. How is the value of x related to the difference of a and b?

cestrela7 [59]

Answer:

The value of x is reciprocal of the difference of a and b.

Step-by-step explanation:

We are given the equation, $ax=bx+1$

On simplifying, we get,

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i.e. $ax-bx=1$

i.e. $(a-b)x=1$

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So, we get,

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2 years ago

69.6% of all full-time law enforcement officers are sworn officers, and of those, 88.2% were males. Females, however, make up 60

Evgen [1.6K]

Answer:

The probability that he or she is a male or a civilian employee is 1.037068

Step-by-step explanation:

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2 years ago

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A rectangle has width that is 6 meters less than the length. The area of the rectangle is 280 square meters. Find the dimensions

salantis [7]

Dimensions are length 20 meter and width 14 meter

Solution:

Let "a" be the length of rectangle

Let "b" be the width of rectangle

Given that,

A rectangle has width that is 6 meters less than the length

Width = length - 6

b = a - 6

The area of the rectangle is 280 square meters

The area of the rectangle is given by formula:

$Area = length \times width$

Substituting the values we get,

$Area = a \times (a-6)\\\\280 = a^2-6a\\\\a^2-6a -280=0$

Solve the above equation by quadratic formula

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=1,\:b=-6,\:c=-280:\quad a_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:1\left(-280\right)}}{2\cdot \:1}$

$a =\frac{6 \pm \sqrt{36+1120}}{2}\\\\a = \frac{6 \pm \sqrt{1156}}{2}\\\\a = \frac{6 \pm 34}{2}\\\\Thus\ we\ have\ two\ solutions\\\\a = \frac{6+34}{2} \text{ or } a = \frac{6-34}{2}\\\\a = 20 \text{ or } a = -14$

Since, length cannot be negative, ignore a = -14

Thus solution of length is a = 20

Therefore,

width = length - 6

width = 20 - 6 = 14

Thus dimensions are length 20 meter and width 14 meter

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3 years ago