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damaskus [11]
3 years ago
15

Help me name this Molecule

Chemistry
1 answer:
Goryan [66]3 years ago
6 0

Answer:

1—methylethyl ethanoate

Explanation:

The compound is named as as follow:

1. Name the group after the O, starting the numbering from the carbon bonding to the O. The name is:

1—methylethyl

2. Name the group before the O, ending the name with —oate. The name name is ethanoate since there are 2 carbon atoms.

Now we combine the names together, starting with the name after the O as illustrated below:

1—methylethyl ethanoate

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When 2.714 g of AX (s) dissolves in 127.4 g of water in a coffee-cup calorimeter the temperature rises from 23.3 °C to 37.1 °C.
MakcuM [25]

Answer : The enthalpy change for the solution is 166.34 kJ/mol

Explanation :

First we have to calculate the enthalpy change of the reaction.

Formula used :

\Delta H=mC\Delta T\\\\\Delta H=mC(T_2-T_1)

where,

\Delta H = change in enthalpy = ?

C = heat capacity of water = 4.18J/g.K

m = total mass of sample = 2.174 + 127.4 = 129.6 g

T_1 = initial temperature = 23^oC=273+23=296K

T_2 = final temperature = 37.1^oC=273+37.1=310.1K

Now put all the given values in the above expression, we get:

\Delta H=mC(T_2-T_1)

\Delta H=129.6g\times 4.18J/g.K\times (310.1-296)K=7638.36J

Now we have to calculate the moles of AX added to water.

\text{ Moles of }AX=\frac{\text{ Mass of }AX}{\text{ Molar mass of }AX}=\frac{2.714g}{59.1097g/mole}=0.04592moles

Now we have to calculate the enthalpy change for the solution.

As, 0.04592 moles releases heat = 7638.36 J

So, 1 moles releases heat = \frac{7638.36}{0.04592}=166340.59J=166.34kJ

Therefore, the enthalpy change for the solution is 166.34 kJ/mol

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3 years ago
What are the components of the system that influence its motion? *
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