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netineya [11]
2 years ago
12

Which of the following is an organic compound

Chemistry
1 answer:
nikitadnepr [17]2 years ago
4 0
Hydrogen, Oxygen and Nitrogen
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Electro magnetic waves are blank waves<br><br> What’s the blank PLEASE HELP DUE IN 25 MINUTES!!!!
Sav [38]

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Electromagnetic waves or EM waves are waves that are created as a result of vibrations between an electric field and a magnetic field. Hope it helps ;)

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3 years ago
Cuál será el volumen de ácido clorhídrico concentrado, de densidad 1,19g/mL del 38% de ácido en peso, que se necesita para prepa
julsineya [31]

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7 0
3 years ago
If a solution containing 45.101 g of mercury(II) acetate is allowed to react completely with a solution containing 12.026 g of s
AnnyKZ [126]

Answer:

14.533 grams of solid precipitate of mercury(II) dichromate will form.

Explanation:

Hg(CH_3COO)_2(aq)+Na_2Cr_2O_7(aq)\rightarrow HgCr_2O_7(s)+2CH_3COONa(aq)

Moles of mercury(II) acetate = \frac{45.101 g}{318.70 g/mol}=0.14152 mol

Moles of sodium dichromate = \frac{12.026 g}{261.97 g/mol}=0.045906 mol

According to reaction , 1 mole of sodium dichromate reacts with 1 mole of mercury(II) acetate , then 0.045906 moles of sodium dichromate will recat with :

\frac{1}{1}\times 0.045906 mol=0.045906 mol of mercury(II) acetate

This means that mercury(II) acetate is present in an excess amount and sodium dichromate is present in limiting amount.So, amount of precipitate will depend upon moles of sodium dichromate.

According to reaction , 1 mole of sodium dichromate gives 1 mole of mercury(II) dichromate , then 0.045906 moles of sodium dichromate will give :

\frac{1}{1}\times 0.045906 mol=0.045906 mol of mercury(II) dichromate

Mass of 0.045906 moles of mercury(II) dichromate:

0.045906 mol × 316.59 g/mol = 14.533 g

14.533 grams of solid precipitate of mercury(II) dichromate will form.

3 0
3 years ago
Identify the difference between natural and artificial dyes.
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The difference between natural dye and synthetic dyes is largely that synthetic dyes are chemically manufactured whereas natural dyes are purely developed from nature.
3 0
3 years ago
The half life of radium-226 is 1600 years. How many grams of a 0.25g sample will remain
myrzilka [38]

Answer:

Explanation:

half life = 1600 years .

m = M  x ( \frac{1}{2} )^n

m is mass of the radioactive object after n half lives , M is original mass.

n = 4800 / 1600

= 4

Putting the valus of n and M we have

m = .25 x ( \frac{1}{2} )^3

= .03125 g .

4 0
3 years ago
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