Ans: The entropy change for the given reaction is 93.3 J/K
Given reaction:
Br2(l) → Br2(g)
ΔS = ∑n(products)S⁰(products) - ∑n(reactants)S⁰(reactants)
= 1 mole* S°(Br2(g)) - 1 mole*S°(Br2(l))
= 1 mole *245.5 J/mol-K - 1 mole*152.2 J/mol-K
= 93.3 J/K
For water to freeze it would need to be 32 degrees Fahrenheit or 0 degrees Celsius.
Glacial till, hope this helps!
Answer:
= 8350 joules
Solution and explanation:
- The heat of fusion refers to the quantity of heat released when a given amount of water freezes.
- For example, 1 g of water releases 334 J when it freezes at 0°C.
Therefore; For 25.0 g of water.
Heat released = Mass of water × heat of fusion
= 25 g × 334 J/g
= 8350 Joules
Hence, the amount of heat released when 25.0 g of water freezes at 0°C is 8350 J.
A.
The first energy level has 2 electrons, the second has 8, and the third has 4
