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ICE Princess25 [194]
3 years ago
13

Which of the following is the major regulator of oxygen consumption during oxidative phosphorylation?

Chemistry
2 answers:
Klio2033 [76]3 years ago
8 0

Answer:

f.ADP

Explanation:

  • <u>Oxidative phosphorylation </u>occurs during the electron transport chain which is the final phase of cellular respiration. It depends on the hydrogen ion concentration gradient generated and is maintained by the electron transport chain.
  • <u>The oxidative phosphorylation acquires energy of high-energy electrons to synthesize ATP. During this process ADP is the major regulator of oxygen consumption.</u>
  • The regulation by ADP is referred to as the acceptor or respiratory control.
aalyn [17]3 years ago
5 0

Answer: F. ADP

Explanation:

The level of ADP is the most important factor in the determination of the rate of Oxidative Phosphorylation.

The rate of oxygen utilization by the Mitochondria is increased when ADP is added and usually returns to its initial level when the added ADP has being converted to ATP.

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What is the molecular formula for a compound with an empirical formula of CH2O if its experimentally determined molecular weight
NNADVOKAT [17]

Answer:

C6H12O6.

Explanation:

Adding up the relative atomic masses of the elements

C + 2H + O

= 12 + 2*1 + 16.

= 30.

180 / 30 = 6  so the molecular formula is:

C6H12O6.

3 0
3 years ago
Magnesium unites completely and vigorously with oxygen to form magnesium oxide, which contains 60% magnesium by weight. If 1.00
Dmitry_Shevchenko [17]

Answer:

After the reaction, there will 0.60 g of magnesium oxide and 0.25 g of oxygen gas present in the tube

Explanation:

Equation of the reaction between magnesium and oxygen is given as follows:

2Mg(s) + O₂(g) ---> 2MgO(s)

From the equation of reaction, 2 moles of magnesium reacts with i mole of oxygen gas to produce 1 mole of magnesium oxide

molar mass of magnesium is 24.0 g; molar mass of oxygen gas = 32.0 g; molar mass of magnesium oxide = 40.0 g

Therefore 24 g of magnesium reacts with 32 g of oxygen gas

I.00 g of magnesium will react with (24.0 / 32.0) * 1.00 g of oxygen = 0.75 g of oxygen gas.

Therefore, magnesium is the limiting reagent. Once it is used up, the reaction will stop and the excess oxygen will be left in the tube together with the product, magnesium oxide.

mass of excess oxygen = 1.00 - 0.75 = 0.25 g

mass of magnesium oxide formed = (24.0 / 40.0 g) * 1 = 0.60 g

4 0
3 years ago
Consider the reaction mg(oh)2(s)→mgo(s)+h2o(l) with enthalpy of reaction δhrxn∘=37.5kj/mol what is the enthalpy of formation of
Anni [7]
Answer is: -601,2 kJ/mol
Chemical reaction: Mg(OH)₂ → MgO + H₂O.
ΔHrxn = 37,5 kJ/mol.
ΔHf(Mg(OH)₂) = <span>−924,5 kJ/mol.
</span>ΔHf(H₂O) = <span>−285,8 kJ/mol.
</span>ΔHrxn -enthalpy of reaction.
ΔHf - enthalpy of formation.
<span>ΔHrxn=∑productsΔHf−∑reactantsΔHf. 
</span>ΔHf(MgO) = -924,5 kJ/mol - (-285,8 kJ/mol) + 37,5 kj/mol.
ΔHf(MgO) = -601,2 kJ/mol.
7 0
3 years ago
Read 2 more answers
What do you call the ability of a gas to completely spread out and mix with other substances?
olganol [36]
The ability for gas to mix with other substances is diffusion.
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When you dissolve an antacid tablet in water and it produces bubbles, what kind of change is this?
prisoha [69]

Answer: B. a chemical change

Explanation:

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