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Sedbober [7]
3 years ago
9

Which is an equation of a circle with center (5, 0) that passes through the point (1, 1)

Mathematics
1 answer:
alex41 [277]3 years ago
7 0

Equation of circle at center (h,k) is given by

(x-h)^2+(y-k)^2=r^2

Given that center is at (5,0) that means h=5 and k=0

plug both values into above formula

(x-5)^2+(y-0)^2=r^2

(x-5)^2+y^2=r^2 ...(i)

Given that circle passes through point (1,1) so it will satisfy above equation

(1-5)^2+1^2=r^2

(-4)^2+1^2=r^2

16+1=r^2

17=r^2

Now plug this value of r^2 into equation (i)

(x-5)^2+y^2=17

which best matches with choice C

Hence (x-5)^2+y^2=17 is the final answer.

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