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Mila [183]
3 years ago
10

Conductors an insulators

Physics
1 answer:
sladkih [1.3K]3 years ago
6 0

Conductors transfer energy (metal is a good one) and insulators stop the transfer of energy (such as rubber or plastic). Sorry if that is wrong, but I hope it helps!

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Very large accelerations can injure the body, especially if they last for a considerable length of time. The severity index (SI)
Ludmilka [50]

Answer:

a) The severity index (SI) is 3047.749, b) The injured travels 0.345 meters during the collision.

Explanation:

a) The g-multiple of the acceleration, that is, a ratio of the person's acceleration to gravitational acceleration, is:

a' = \frac{35\,\frac{m}{s^{2}} }{9.807\,\frac{m}{s^{2}} }

a' = 3.569

The time taken for the injured to accelerate to final speed is given by this formula under the assumption of constant acceleration:

v_{f} = v_{o} + a \cdot t

Where:

v_{o} - Initial speed, measured in meters per second.

v_{f} - Final speed, measured in meter per second.

a - Acceleration, measured in \frac{m}{s^{2}}.

t - Time, measured in seconds.

t = \frac{v_{f}-v_{o}}{a}

t = \frac{\left(12\,\frac{km}{h} \right)\cdot \left(1000\,\frac{m}{km} \right)\cdot \left(\frac{1}{3600}\,\frac{h}{s}  \right)}{35\,\frac{m}{s^{2}} }

t = 0.095\,s

Lastly, the severity index is now determined:

SI = \frac{a'^{5}}{2\cdot t}

SI = \frac{3.569^{5}}{2\cdot (0.095\,s)}

SI = 3047.749

b) The initial and final speed of the injured are 1.944\,\frac{m}{s} and 5.278\,\frac{m}{s}, respectively. The travelled distance can be determined from this equation of motion:

v_{f}^{2} = v_{o}^{2} + 2\cdot a \cdot \Delta s

Where \Delta s is the travelled distance, measured in meters.

\Delta s = \frac{v_{f}^{2}-v_{o}^{2}}{2\cdot a}

\Delta s = \frac{\left(5.278\,\frac{m}{s} \right)^{2}-\left(1.944\,\frac{m}{s} \right)^{2}}{2\cdot \left(35\,\frac{m}{s^{2}} \right)}

\Delta s = 0.345\,m.

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3 years ago
I need help on 7 and 8 thanks
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3 years ago
An object of mass m has these three forces acting on it (there is no normal force, "no surface"). F1 = 1 N, F2 = 9 N, and F3 = 5
hammer [34]

Answer:

solved

Explanation:

a) F_net = (F2 - F3)i - F1 j

b) |Fnet| = sqrt( (F2 - F3)^2 + F1^2)

= sqrt( (9- 5)^2 + 1^2)

= 4.123 N

c) θ = tan^-1( (Fnet_y/Fnet_x)

= tan^-1( -1/(9-5) )

= -14.036°

7 0
3 years ago
Science requires theories that can be tested by research. true false
dezoksy [38]
True Requires the development of theories that can be tested by systematic research.
3 0
3 years ago
You have a pulley 10.4 cm in diameter and with a mass of 2.3 kg. You get to wondering whether the pulley is uniform. That is, is
madreJ [45]

Answer:

Explanation:

Given

Diameter of Pulley=10.4 cm

mass of Pulley(m)=2.3 kg

mass of book(m_0)=1.7 kg

height(h)=1 m

time taken=0.64 s

h=ut+frac{at^2}{2}

1=0+\frac{a(0.64)^2}{2}

a=4.88 m/s^2and [tex]a=\alpha r

where \alphais angular acceleration of pulley

4.88=\alpha \times 5.2\times 10^{-2}

\alpha =93.84 rad/s^2

And Tension in Rope

T=m(g-a)

T=1.7\times (9.8-4.88)

T=8.364 N

and Tension will provide Torque

T\times r=I\cdot \alpha

8.364\times 5.2\times 10^{-2}=I\times 93.84

I=0.463\times 10^{-2} kg-m^2

I_{original}=\frac{mr^2}{2}=0.31\times 10^{-2}kg-m^2

Thus mass is uniformly distributed or some more towards periphery of Pulley

4 0
3 years ago
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