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2 years ago

PLEASE HELP ASAP.....!! 10 pts

Mathematics

1 answer:

ICE Princess25 [194]2 years ago

5 0

Answer:

Possible dimensions are 16 × 4 inches and 32 × 2 inches.

Step-by-step explanation:

We are given that,

Area of the frame = 64 inch² = Length × Width

Now, we have that 64 can be factored as,

64 = 32 × 2

64 = 16 × 4

64 = 8 × 8

Since, the frame is in a rectangular shape. So, we reject the possibility of 8 × 8 inches frame.

Thus, the possible dimensions are,

Set 1: 16 × 4 inches

Set 2: 32 × 2 inches.

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Someone pls help me i do not understand !!

pantera1 [17]

Yea me ether did you ever find the answer

3 0

2 years ago

A block of glass has a mass of 22.5g and a volume of 9cm cubed.

melisa1 [442]

Answer:

density, mass of a unit volume of a material substance. The formula for density is d = M/V, where d is density, M is mass, and V is volume. Density is commonly expressed in units of grams per cubic centimetre.

Step-by-step explanation:

3 0

1 year ago

Find parametric equations and symmetric equations for the line. (Use the parameter t.) The line through (4, −5, 2) and parallel

Nataliya [291]

Answer:

Step-by-step explanation:

From the given information, the symmetric equations for the line pass through(4, -5, 2) i.e ( $x_o, y_o, z_o$ ) and are parallel to $\dfrac{x+5}{1} = \dfrac{y}{2}= \dfrac{z-3}{1}$

The parallel vector to the line i + zj+k = ai + bj + ck

Hence, the equation for the line is :

$x = x_o + at \\ \\ x = y_o + bt \\ \\ x = z_o + ct$

x = 4 + t

y = -5 + 2t

z = 2 + t

Thus, x, y, z = ( 4+t, -5+2t, 2+t )

The symmetric equation can now be as follows:

$\begin {vmatrix} x = 4+ t \\ \\ \dfrac{x-4}{1} = t \begin {vmatirx} \end {vmatrix}$ $\begin {vmatrix} y = - 5+2t \\ \\ \dfrac{y+5}{2} =t \end {vmatrix}$ $\begin {vmatrix} z =2+t \\ \\ \dfrac{z-2}{1} =t \end {vmatrix}$

∴

$\dfrac{x-4}{1}= \dfrac{y+5}{2}=\dfrac{z-2}{1}$

8 0

2 years ago

Suppose a white dwarf star has a diameter of approximately 1.8083 to the power of 4 km. Use the formula 4n to the power of 2 to

aivan3 [116]

ANSWER:

The surface area of the star is 3.2700 x $10^{8}$ square kilometres.

EXPLANATIONS:

Diameter of the star = 1.8083 x $10^{4}$ Km.

Surface area of the star = 4 $n^{2}$

Where n is the radius of the star.

So that;

n = $\frac{ 1.8083 * 10^{4} }{2}$

= 0.90415 x $10^{4}$

n = 0.90415 x $10^{4}$ Km

Thus,

Surface area = 4 x $(0.90415*10^{4} )^{2}$

= 326994889

Surface area = 3.2700 x $10^{8}$ $km^{2}$

Therefore, the surface area of the star is 3.2700 x $10^{8}$ square kilometres.

4 0

2 years ago

Divide. Write the quotient in lowest terms. 1/4 ÷ 1 1/8<br><br>

natta225 [31]

Answer:2/11

Step-by-step explanation:

A fraction is in simplest form when the top and bottom cannot be any smaller

Firstly start by getting the common factors between 1 and 4 in 1/4 and 11 and 8 in 11/8. The common factor is 1 in 1/4 and 1 in 11/8. 1÷1/4÷1= 1/4. 11÷1/8÷1 = 11/8.

1/4÷ 11/8 =2/11.

3 0

3 years ago

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