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Tatiana [17]
4 years ago
13

50 COINS AMAZING PLEASE HELP ME!!!

Physics
1 answer:
algol [13]4 years ago
8 0

Answer:

ok

Explanation:

Ok

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A change in ________ results in ________.
Triss [41]
I think it's C. I may be wrong, tho
3 0
3 years ago
How much time would it take for an
Elina [12.6K]

36 and a half hours

Explanation:

4 0
4 years ago
What effect does the Sun have on the ocean tides?
Degger [83]

Answer:

B

Explanation:

When the sun, moon, and Earth are in alignment at the time of the new or full moon, the solar tide has an additive effect on the lunar tide, creating extra-high high tides, and very low, low tides both commonly called spring tides.

8 0
3 years ago
An 80-kg bungee jumper jumps off a bridge. Rubber bungee cords act as a large spring attaching the jumper to the bridge. A bear
inysia [295]

Answer:

The force is F_b =  216 \  N

Explanation:

From the question we are told that

   The  mass of the bungee jumper is  m  = 80 kg

    The spring constant is  k =  20 \  N/ m

    The extension of the rubber bungee cords is  x = 50 m

Generally the weight of the jumper is

      W =  m *  g

=>   W =  80 *  9.8

=>   tex]W =  784  \  N  [/tex]

Generally  the returning force of the rubber bungee cords is mathematically represented as

      F  =  k  *  x

=>     F  =  20   * 50

=>     F  =  1000 \  N

The force to be applied by the bear is

    F_b =  F -  W

=>    F_b =  100 -  784

=>  F_b =  216 \  N

6 0
3 years ago
A 2.0 kg block is given an initial speed of 8.0 m/s up an incline plane of angle 30° where the coefficient of friction is 0.35.
Korvikt [17]

Answer:

4.1 m

Explanation:

Given :

Mass of the block = m = 2 kg.

Initial velocity = v_{i} = 8 m/s

Angle of the incline = α = 30°

Coefficient of friction = μ = 0.35

Distance moved up the incline is calculated using the work energy theorem.

Work done by the net force =  change in kinetic energy of the object.

Net work = work done by friction + work done by the gravity component.

(- mg sin 30 - μ mg cos 30 ) d = 1/2m v_{f}^{2} - 1/2 m v_{i}^{2}

m cancels out when divided on both sides with m.

- [(9.8 sin 30 - ( 0.35  × 9.8 × cos 30) ] d = 1/2 ( 0² - 8² )

⇒ -7.87 d = -32

⇒ Distance traveled up the incline = d = 4.0658 m = 4.1 m

8 0
4 years ago
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