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3 years ago

If no external forces act on a moving object it will

Physics

2 answers:

MA_775_DIABLO [31]3 years ago

6 0

Stay moving the same speed Hope this helps! ;D

mario62 [17]3 years ago

5 0

So we want to know what happens to a moving object if no external forces act on it. So Newtons first law states that the object will continue moving with constant velocity or continue to stand still if no external force is acting on the object. So the correct answer is If no external forces act on a moving object it will continue to move with constant velocity.

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Duane skis down a hill at an angle of 42°. He has a mass of 92 kg. What is the normal force on Duane?

Sindrei [870]

Normal force=m*g*cos theta
normal force=92kg*9.8m/s^2*cos 42
normal force=670 N

7 0

3 years ago

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A makeshift sign hangs by a wire that is extended over an ideal pulley and is wrapped around a large potted plant on the

ella [17]

Answer:I know the answer for B cus I’m doing the same problem. For B, you would only take the coefficient of friction given and then multiply it by the Normal Force, which in this case is the same as the Gravitational Force.

Explanation:

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3 years ago

Radon-222 ( 222/86 Rn) is a radioactive gas with a half-life of 3.82 days. A gas sample contains 4.1 e 8 radon atoms initially.

kow [346]

Answer :

(a) The number of radon atoms will remain after 12 days is, $4.67\times 10^7$

(b) The number of radon nuclei have decayed by this time will be, $3.6\times 10^8$

Explanation :

Half-life = 3.82 days

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{3.82\text{ days}}$

$k=1.81\times 10^{-1}\text{ days}^{-1}$

Now we have to calculate the number of radon atoms will remain after 12 days.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $1.81\times 10^{-1}\text{ days}^{-1}$

t = time passed by the sample = 12 days

a = initially number of radon atoms = $4.1\times 10^8$

a - x = number of radon atoms left = ?

Now put all the given values in above equation, we get

$12=\frac{2.303}{1.81\times 10^{-1}}\log\frac{4.1\times 10^8}{a-x}$

$a-x=4.67\times 10^7$

Thus, the number of radon atoms will remain after 12 days is, $4.67\times 10^7$

Now we have to calculate the number of radon nuclei will have decayed by this time.

The number of radon nuclei have decayed = Initial number of radon atoms - Number of radon atoms left

The number of radon nuclei have decayed = $(4.1\times 10^8)-(4.67\times 10^7)$

The number of radon nuclei have decayed = $3.6\times 10^8$

Thus, the number of radon nuclei have decayed by this time will be, $3.6\times 10^8$

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3 years ago

Red light has a _____ wavelength and a _____ frequency than does blue light.

Harlamova29_29 [7]

In a spectrum of visible light, we will see that red appears to have a longer wavelength than the blue light. Since wavelength and frequency are inversely proportional then, red will have a smaller frequency than does the blue light.

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4 years ago

Why does a boat that is bumped by a wave not actually move to another position in the water

cluponka [151]

Explanation:

due to its shape st the bottom

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4 years ago