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faust18 [17]
3 years ago
6

Two thirds of a number reduced by 11 is equal to 4 more than the number. Find the number.

Mathematics
1 answer:
jeyben [28]3 years ago
8 0

Answer:

b

Step-by-step explanation:

Let x be that number

The equation will be the following:

● (2/3)x - 11 = x + 4

Add 11 to both sides

● (2/3)x - 11 + 11 = x + 4 + 11

● (2/3)x = x + 15

Add -x to both sides

● (2/3)x - x = x + 15 - x

● 2x -3x/3 = 15

● -x/3 = 15

Multiply both sides by -3

● -x/3 × 3 = 15 × -3

● x = -45

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The height of the Washington monument is 555.146.

I got this by using trigonometry “tan(77) • 118”
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3 years ago
The table shows the value of an account x years after the account was opened. Based on the exponential regression model, which i
lana66690 [7]

Answer:

Correct choice is B

Step-by-step explanation:

The exponential regression model can be written as exponential function

y=a\cdot b^x.

Then

5,000=a\cdot b^0=a,\\ \\5,510=a\cdot b^2\Rightarrow 5,510=5,000\cdot b^2,\\ \\b^2=\dfrac{5,510}{5,000}=\dfrac{551}{500}\Rightarrow b\approx 1.05.

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6 0
4 years ago
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A ramp 18 ft long rises to a platform. The bottom of the platform is 13 ft from the foot of the ramp. Find x, the angle of eleva
Varvara68 [4.7K]

Answer:

The answer to your question is: Ф = 43.95°

Step-by-step explanation:

Data

length = 18 ft

distance bottom to is 13 ft

x = angle = ?

Formula

cos Ф = opposite side / hypotenuse  

Process

cos Ф = 13 ft / 18 ft                   substitution

cos Ф = 0.72                            simplify

Ф = cos⁻¹ (0.72)

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8 0
4 years ago
What are the factors of 2x + 3x - 54? Select two options
tiny-mole [99]

Answer:

The answer: The factors are (2x-9) and (x+6).

The Problem:

Factor 2x^2+3x-54

Step-by-step explanation:

So I'm going to do trial factors using the choices to aid me.

Factored form for this problem if it exist will be in the form:

(mx+n)(kx+p).

In general this is what it would look like if we factored any quadratic in terms of x (given the quadratic is not prime but technically you could factor even over the complex numbers).

Let's look at:

(mx+n)(kx+p)

We want to choose k \text{ and } m such that when you multiply them you get 2.  Well those would have to be 2 and 1.

(2x+n)(x+p)

we want to choose n \text{ and } p such that when you multiply them you get -54. Based on the choices we want to get with -9 and 6, or 9 and -6. We don't know the order we want to choose it in either.

For example which of these would work:

(2x-6)(x+9)

(2x+6)(x-9)

(2x-9)(x+6)

(2x+9)(x-6)

We are going to consider only the outer and inner of FOIL since we already know the first times the first is 2x^2 and the last times the last is -54.

Let's test the first one:

(2x-6)(x+9)

Outer:  2x(9)=18x

Inner: -6(x)=-6x

------------------------ADD!

18x-6x=12x

The first choice did not give us the middle term 3x.

Trying the second one would give us the opposite since they are in the same form as previous just the + and - are switched.

Let's look at the third one:

(2x-9)(x+6)

Outer: 2x(6)=12x

Inner: -9(x)=-9x

--------------------------ADD!

12x-9x=3x

This is the winner.

The answer: The factors are (2x-9) and (x+6).

7 0
3 years ago
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!!!!!!!!!!!!!!!!!!!!
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3. 152 i think that is it
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3 years ago
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