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DiKsa [7]
4 years ago
6

Write 15b^2/3b^2+9b in the lowest terms.

Mathematics
1 answer:
Neko [114]4 years ago
7 0

15b^2/3b(b+3)

5b/b+3

That the answer

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For the given triangle, x = 5.1 cm and y = 6.1 cm.

Step-by-step explanation:  

Step 1:  

In the given triangle, the angle is 50°. It is given that the opposite side has a length of y cm and the adjacent side has a length of y cm.   The hypotenuse of the triangle measures 8 cm.

To determine the length of the opposite side of the triangle, we use the sin of the given angle.  

To determine the length of the adjacent side of the triangle, we use the cos of the given angle.  

sin \theta = \frac{oppositeside}{hypotenuse} , cos \theta = \frac{adjacentside}{hypotenuse}.

Step 2:  

In the given triangle,  

The length of the opposite side = y cm,  

The length of the adjacent side = x cm,  

The length of the hypotenuse = 8 cm,  

The angle of the triangle = 50°.

sin \theta = \frac{oppositeside}{hypotenuse} , sin 50 = \frac{y}{8}.

y = 0.7660 (8) = 6.128.

cos \theta = \frac{adjacentside}{hypotenuse} , cos 50 = \frac{x}{8}.

x = 0.6427 (8) = 5.1416.

So x = 5.1416 cm and y = 6.128 cm. Rounding these off to one decimal place, we get x = 5.1 cm and y = 6.1 cm.

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