<span>F= ma force is directed on the working surface so 40 = m x 2 hence
m must be 20 units needed are probably kg</span>
(c)p→π⁺₊π⁺₊π
Baryon number is +1 on the left side of the equation, 0 on the
right side. Baryon number is not conserved.
<h3>How do you determine whether a baryon number is conserved?</h3>
- According to the law of conservation of baryon number, the sum of the baryon numbers of all incoming particles equals the sum of the baryon numbers of all particles produced by the reaction. Energy, and so on, are conserved even if the incoming proton has sufficient energy and charge.
<h3>What is Baryon Number</h3>
- In particle physics, the baryon number denotes which particles are baryons and which particles are not. Each baryon has a baryon number of 1, and each antibaryon has a baryon number of -1. Other non-baryonic particles have a baryon number of 0. Since there are exotic hadrons like pentaquarks and tetraquarks, there is a general definition of baryon number as:
- B=1/3(
)
- where
represents the number of quarks and nq represents the number of antiquarks.
To learn more about Baryon Number refer to
brainly.com/question/10358797
#SPJ4
Answer:
The answer is C.move forward rapidly until stopped.
Explanation:
50 miles an hour is a very high speed. The momentum transfer to the car at stop light will move the car forward rapidly until its brake is able to stop it.
Answer:
E
Explanation:
A vector is a physical quantity that has magnitude and direction while a scalar is a physical quantity that has magnitude only
*electric potential is a scalar quantity because it only has magnitude
*electric field and electric force are vector quantities because they have magnitude and direction
Answer:
v = 15.8 m/s
Explanation:
Let's analyze the situation a little, we have a compressed spring so it has an elastic energy that will become part kinetic energy and a potential part for the man to get out of the barrel, in addition there is a friction force that they perform work against the movement. So the variation of mechanical energy is equal to the work of the fictional force
= ΔEm =
-Em₀
Let's write the mechanical energy at each point
Initial
Em₀ = Ke = ½ k x²
Final
= K + U = ½ m v² + mg y
Let's use Hooke's law to find compression
F = - k x
x = -F / k
x = 4400/1100
x = - 4 m
Let's write the energy equation
fr d = ½ m v² + mgy - ½ k x²
Let's clear the speed
v² = (fr d + ½ kx² - mg y) 2 / m
v² = (40 4.00 + ½ 1100 4² - 60.0 9.8 2.50) 2/60.0
v² = (160 + 8800 - 1470) / 30
v = √ (229.66)
v = 15.8 m/s