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Vikki [24]
3 years ago
8

.

Physics
1 answer:
Kryger [21]3 years ago
7 0
Ionic compound, it's HCL and it's hydrologic acid
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A light bulb has a power rating of 60 W. What is the current running into it if it is plugged into a 120 V outlet?
kifflom [539]

Answer:

0.5 Amperes

Explanation:

Information that we have:

Power: P=60W

Voltage: V=120V

and we use the equation that relates this two quantities to the Current (I):

I=\frac{P}{V}

where I is the curent, P is the Power and V is the Voltage.

we substitute the values given for the Power and the Voltage to find the current:

I=\frac{60W}{120V}\\ I=0.5A

the Current running into the bulb is 0.5 Amperes

3 0
3 years ago
What is moment and it's type​
olga2289 [7]

Explanation:

The turning effect of a force is called moment .

There are two types of moment. They are:-

  • clockwise moment
  • anti-clockwise moment
8 0
3 years ago
How does geosphere interact with biosphere
Marina86 [1]

<span>With a partner, describe interactions in this scene, tracing the movement of materials or energy through all four of Earth's spheres if possible. Plants (biosphere) draw water (hydrosphere) and nutrients from the soil (geosphere) and release water vapor into the atmosphere.</span>
6 0
3 years ago
What is the on ohooke benden
-Dominant- [34]

Answer:Work is the energy required to move an object from one point to another. while power is the energy transferred per unit time.

6 0
3 years ago
A 3.9 kg block is pushed along a horizontal floor by a force of magnitude 30 N at a downward angle θ = 40°. The coefficient of k
Luba_88 [7]

Answer:

The frictional force  F_{fri} = 6.446 N

The acceleration of the block a = 6.04 \frac{m}{s^{2} }

Explanation:

Mass of the block = 3.9 kg

\theta = 40°

\mu = 0.22

(a). The frictional force is given by

F_{fri} = \mu R_{N}

R_{N} = mg \cos \theta

R_{N} = 3.9 × 9.81 × \cos 40

R_{N} = 29.3 N

Therefore the frictional force

F_{fri} = 0.22 × 29.3

F_{fri} = 6.446 N

(b). Block acceleration is given by

F_{net} = F - F_{fri}

F = 30 N

F_{fri} = 6.446 N

F_{net} = 30 - 6.446

F_{net} = 23.554 N

The net force acting on the block is given by

F_{net}  = ma

23.554 = 3.9 × a

a = 6.04 \frac{m}{s^{2} }

This is the acceleration of the block.

8 0
3 years ago
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