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zlopas [31]
3 years ago
14

A ramp is used to load furniture onto a moving truck. The person does 1240 J of work pushing

Physics
1 answer:
Len [333]3 years ago
6 0

Answer:

The efficiency of the ramp is, Eff = 6.63 %

Explanation:

Given,

The work done by the person pushing the furniture up the ramp is, W₁ = 1240 J

The work done by the ramp is, W₀ = 822 J

The efficiency of the ramp is given by the formula,

                                 <em> Eff = ( W₀ / W₁ ) x 100%</em>

                                        = ( 822 / 12400 ) x 100%

                                        = 6.63 %

Hence, the efficiency of the ramp is, Eff = 6.63 %

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a) v = 21.34 m/s

b) v = 21.34 m/s

c) v = 21.34 m/s

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Mass of the snowball, m = 0.560 kg

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θ = 26°

The speed of the slow ball as it reaches the ground, v = ?

The initial Kinetic energy of the snow ball, KE_{0}  = 0.5 mu^{2}

Potential energy of the snow ball at the given height, PE = mgh

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KE_{0} + PE = KE_{f} \\0.5mu^{2} + mgh = 0.5mv^{2}\\v^{2} =2( 0.5u^{2} + gh)\\v^{2} =u^{2} + 2gh\\v = \sqrt{u^{2} + 2gh} \\v = \sqrt{13.3^{2} + 2*9.8*14.2}\\v = 21.34 m/s

b) The speed remains v = 21.34 m/s since it is not a function of the angle of launch

c)The principle of energy conservation used cancels out the mass of the object, therefore the speed is not dependent on mass

v = 21. 34 m/s

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