The lever is a movable bar that pivots on a fulcrum attached to or positioned on or across a fixed point. The lever operates by applying forces at different distances from the fulcrum, or pivot.
A lever amplifies an input force to provide a greater output force, which is said to provide leverage. The ratio of the output force to the input force is the mechanical advantage of the lever.
The mechanical advantage of the lever is increased by moving the fulcrum closer to the load i.e., by shifting the fulcrum towards the right. Moving the fulcrum away from the load has mechanical disadvantage as the distance between the load and the fulcrum increases, the input force becomes greater than the output force.
Answer:
A: The wave is a mechanical wave.
C: The wave moves energy through matter.
F: The wave transfers energy perpendicular to the motion of the wave.
The increase in potential energy is ![5.95\cdot 10^4 J](https://tex.z-dn.net/?f=5.95%5Ccdot%2010%5E4%20J)
Explanation:
The gravitational potential energy gained by an object lifted above the ground is given by:
![\Delta PE = mg \Delta h](https://tex.z-dn.net/?f=%5CDelta%20PE%20%3D%20mg%20%5CDelta%20h)
where
m is the mass of the object
g is the acceleration of gravity
is the change in height of the object
For the beam in this problem, we have
m = 330 kg
![g=9.8 m/s^2](https://tex.z-dn.net/?f=g%3D9.8%20m%2Fs%5E2)
![\Delta h = 18.4 m](https://tex.z-dn.net/?f=%5CDelta%20h%20%3D%2018.4%20m)
Substituting, we find its gain in potential energy:
![\Delta PE=(330)(9.8)(18.4)=5.95\cdot 10^4 J](https://tex.z-dn.net/?f=%5CDelta%20PE%3D%28330%29%289.8%29%2818.4%29%3D5.95%5Ccdot%2010%5E4%20J)
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If the observer is moving away from the source ((Figure)), the observed frequency can be found: λs=vTo−voTovTs=(v−vo)Tov(1fs)=(v−vo)(1fo)fo=fs(v−vov).
Answer:
14.3 km
Explanation:
We motion of the car consists is split in two parts:
- A first motion 12 km north
- A second motion 7.8 km west
The two motions are in directions perpendicular to each other: this means that we can find the magnitude of the net displacement by using Pythagorean's theorem, therefore:
![d=\sqrt{d_1^2+d_2^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7Bd_1%5E2%2Bd_2%5E2%7D)
where
![d_1 = 12 km](https://tex.z-dn.net/?f=d_1%20%3D%2012%20km)
![d_2 = 7.8 km](https://tex.z-dn.net/?f=d_2%20%3D%207.8%20km)
Substituting, we find
![d=\sqrt{12^2+7.8^2}=14.3 km](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B12%5E2%2B7.8%5E2%7D%3D14.3%20km)