Answer:
The speed of the sled is 3.56 m/s
Explanation:
Given that,
Mass = 2.12 kg
Initial speed = 5.49 m/s
Coefficient of kinetic friction = 0.229
Distance = 3.89 m
We need to calculate the acceleration of sled
Using formula of acceleration
![a = \dfrac{F}{m}](https://tex.z-dn.net/?f=a%20%3D%20%5Cdfrac%7BF%7D%7Bm%7D)
Where, F = frictional force
m = mass
Put the value into the formula
![a=\dfrac{\mu mg}{m}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7B%5Cmu%20mg%7D%7Bm%7D)
![a=\mu g](https://tex.z-dn.net/?f=a%3D%5Cmu%20g)
![a=0.229\times9.8](https://tex.z-dn.net/?f=a%3D0.229%5Ctimes9.8)
![a=2.244\ m/s^2](https://tex.z-dn.net/?f=a%3D2.244%5C%20m%2Fs%5E2)
We need to calculate the speed of the sled
Using equation of motion
![v^2=u^2-2as](https://tex.z-dn.net/?f=v%5E2%3Du%5E2-2as)
Where, v = final velocity
u = initial velocity
a = acceleration
s = distance
Put the value in the equation
![v ^2=(5.49)^2-2\times2.244\times3.89](https://tex.z-dn.net/?f=v%20%5E2%3D%285.49%29%5E2-2%5Ctimes2.244%5Ctimes3.89)
![v=\sqrt{(5.49)^2-2\times2.244\times3.89}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B%285.49%29%5E2-2%5Ctimes2.244%5Ctimes3.89%7D)
![v=3.56\ m/s](https://tex.z-dn.net/?f=v%3D3.56%5C%20m%2Fs)
Hence, The speed of the sled is 3.56 m/s.
Answer: d= 0.57* l
Explanation:
We need to check that before ladder slips the length of ladder the painter can climb.
So we need to satisfy the equilibrium conditions.
So for ∑Fx=0, ∑Fy=0 and ∑M=0
We have,
At the base of ladder, two components N₁ acting vertical and f₁ acting horizontal
At the top of ladder, N₂ acting horizontal
And Between somewhere we have the weight of painter acting downward equal to= mg
So, we have N₁=mg
and also mg*d*cosФ= N₂*l*sin∅
So,
d=
* tan∅
Also, we have f₁=N₂
As f₁= чN₁
So f₁= 0.357 * 69.1 * 9.8
f₁= 241.75
Putting in d equation, we have
d=
* tan 58
d= 0.57* l
So painter can be along the 57% of length before the ladder begins to slip
Answer:
mass = 0.18 [kg]
Explanation:
This is a classic problem where we can apply the definition of density which is equal to mass over volume.
![density = \frac{mass}{volume} \\\\where:\\volume = 1 [m^3]\\density = 0.18[kg/m^3]](https://tex.z-dn.net/?f=density%20%3D%20%5Cfrac%7Bmass%7D%7Bvolume%7D%20%5C%5C%5C%5Cwhere%3A%5C%5Cvolume%20%3D%201%20%5Bm%5E3%5D%5C%5Cdensity%20%3D%200.18%5Bkg%2Fm%5E3%5D)
mass = 0.18*1
mass = 0.18 [kg]
Answer:
If the frequency is doubled the wavelength is only half as long.If you put your fingertip in a pool of water and repeatedly move it up and down,you will create circular water waves.
Hope this helps!!!