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zimovet [89]
2 years ago
14

How do we use energy transformation in our daily lives?

Physics
2 answers:
Varvara68 [4.7K]2 years ago
6 0
We pick up cups and place them in different places
olga55 [171]2 years ago
4 0

Answer:hat are some examples of energy transformation?

The Sun transforms nuclear energy into heat and light energy.

Our bodies convert chemical energy in our food into mechanical energy for us to move.

An electric fan transforms electrical energy into kinetic energy.

Explanation:

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What is the magnitude of the momentum of a 3400 kg airplane traveling at a speed of 450 miles per hour?
Vitek1552 [10]

Answer:

The magnitude of momentum of the airplane is 6.83\times 10^5\ kg-m/s.

Explanation:

Given that,

Mass of the airplane, m = 3400 kg

Speed of the airplane, v = 450 miles per hour

Since, 1 mile per hour = 0.44704 m/s

v = 201.16 m/s

We need to find the magnitude of momentum of the airplane. It is given by the product of mas and velocity such that,

p=mv

p=3400\ kg\times 201.16 \ m/s

p=683944\ kg-m/s

or

p=6.83\times 10^5\ kg-m/s

So, the magnitude of momentum of the airplane is 6.83\times 10^5\ kg-m/s. Hence, this is the required solution.

7 0
3 years ago
Read 2 more answers
A 100kg crate slides along a floor with a starting velocity of 21ms If the force due to friction is 8N how long will it take for
GaryK [48]

A 100kg crate slides along a floor with a starting velocity of 21 m/s. If the force due to friction is 8N, then, it will take 262.5 s for the box to come to rest.

We'll begin by calculating the declaration of the box. This can be obtained as follow:

Force (F) = –8 N (opposition)

Mass (m) = 100 Kg

<h3>Deceleration (a) =? </h3>

<h3>F = ma</h3>

–8 = 100 × a

Divide both side by 1000

a = \frac{-8}{100}

<h3>a = –0.08 ms¯²</h3>

Therefore, the deceleration of the box is –0.08 ms¯²

Finally, we shall determine the time taken for the box to come to rest. This can be obtained as follow:

Deceleration (a) = –0.08 ms¯²

Initial velocity (u) = 21 ms¯¹

Final velocity (v) = 0 ms¯¹

<h3>Time (t) =.? </h3>

<h3>v = u + at</h3>

0 = 21 + (–0.08×t)

0 = 21 – 0.08t

Collect like terms

0 – 21 = –0.08t

–21 = –0.08t

Divide both side by –0.08

t = \frac{-21}{-0.08}\\\\

<h3>t = 262.5 s</h3>

Therefore, it will take 262.5 s for the box to come to rest.

Learn more: brainly.com/question/14446351

7 0
2 years ago
a gym consists of a rectangular region with a semi-circle on each end. if the perimeter of the room is to be a 200 m running tra
Nikolay [14]

The dimensions of the rectangle are:

l = 50 m

b = 100/\pi m

<h3>What is a perimeter in math?</h3>

The perimeter is the length of the outline of a shape. To find the perimeter of a rectangle or square you have to add the lengths of all the four sides.

<h3>How do we find a perimeter of a rectangle?</h3>

The perimeter of a rectangle,denoted by P is given by the formula, P=2l+2b, where l is the length and b is the breadth of the rectangle.

<h3>Given:</h3>

As per the question:

Perimeter of the room is given as P = 200 m

The region is rectangular having a semicircle at each end.

Now,

Let 'l' be the length of the rectangle, 'b' be its breadth and 'r' be the radius of the semi-circle at each end.

Then, Area of the given rectangle, A = lb

Perimeter of the room, P is =\pi r+l+\pi r+l=2\pi r+2l=\pi b+2l

Therefore,  \pi b+2l=200

b=(200-2l)/\pi

Now,

Area, A = l(200-2l)/\pi=(200l-2l^{2} )/\pi

Now, differentiate A w.r.t l:

Again differentiating w.r.t 'l', we get:

d^{2} A/dl^{2} =-4l/\pi< 0

Thus we get maximum are when dA/dl=0

Therefore,

(200-4l)/\pi=0

l = 50 m

Now, from

\pi b+2l=200

\pi b=200-2*50

b=100/\pi

r=b/2=50/\pi

To know more about area of a recatangle, visit the link

brainly.com/question/20693059

#SPJ4

4 0
1 year ago
HELP DUE TODAY
olga2289 [7]
The answer is B I think sorry if it’s wrong
3 0
3 years ago
A 5 kg mass is oscillating on a spring with a time period of 2.8 seconds. What is the spring constant k of the spring?
katrin [286]

Answer:

<em>k = 25.18 N/m</em>

Explanation:

<u>Simple Harmonic Oscillator</u>

It consists of a weight attached to one end of a spring being allowed to move forth and back.

If m is the mass of the weight and k is the constant of the spring, the period of the oscillation is given by:

\displaystyle T=2\pi {\sqrt {\frac {m}{k}}}

If the period is known, we can find the value of the constant by solving for k:

\displaystyle k=m\left(\frac{2\pi}{T}\right)^2

Substituting the given values m=5 Kg and T=2.8 seconds:

\displaystyle k=5 \left(\frac{2\pi}{2.8}\right)^2

k = 25.18 N/m

5 0
3 years ago
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