All categories

4 years ago

When the fulcrum is shifted to the right, which side has a mechanical advantage and which side has a mechanical disadvantage?

1 answer:

8 0

The lever is a movable bar that pivots on a fulcrum attached to or positioned on or across a fixed point. The lever operates by applying forces at different distances from the fulcrum, or pivot.

A lever amplifies an input force to provide a greater output force, which is said to provide leverage. The ratio of the output force to the input force is the mechanical advantage of the lever.

The mechanical advantage of the lever is increased by moving the fulcrum closer to the load i.e., by shifting the fulcrum towards the right. Moving the fulcrum away from the load has mechanical disadvantage as the distance between the load and the fulcrum increases, the input force becomes greater than the output force.

You might be interested in

A sample of Bismuth-212 has a mass of 2.64 grams (g) after 121 seconds (s). What was the initial mass of the sample if Bismuth-2

uysha [10]

The mass of a radioactive element at time t is given by
$m(t) = m_0 ( \frac{1}{2} )^{ \frac{t}{t_{1/2}} }$
where $m_0$ is the mass at time zero, while $t_{1/2}$ is the half-life of the element.

In our problem, $m(t)=2.64 g$ , t=121.0 s and $t_{1/2}=60.5 s$ , so we can find the initial mass $m_0$ :
$m_0= \frac{m(t)}{ (\frac{1}{2})^{t/t_{1/2}} } = \frac{2.64 g}{( \frac{1}{2} )^{121/60.5}} =4 \cdot 2.64 g=10.56 g$

4 0

3 years ago

4. Compara. La composición de la gasolina para los coches cambia del invierno al verano. La mezcla de los componentes de la gaso

dedylja [7]

Skisosjssnbxhxsndjsksksksa

5 0

3 years ago

What kind of surface is suitable for infared radiation

nlexa [21]

Answer:

Different surfaces

<h3>You can see that dull surfaces are good absorbers and emitters of infrared radiation. Shiny surfaces are poor absorbers and emitters (but they are good reflectors of infrared radiation</h3>

8 0

3 years ago

PLEASEEE HELPPPPPPP:

tatuchka [14]

V(voltage) = I(current)R(resistance)
substitute in the values

V = 15 * 0.10
V = 1.5 volts

7 0

3 years ago

Read 2 more answers

A 1.0-kg block of aluminum is at a temperature of 50 Celsius. How much thermal energy will it lose when it’s temperature is redu

Ipatiy [6.2K]

Answer:

The lose of thermal energy is, Q = 22500 J

Explanation:

Given data,

The mass of aluminium block, m = 1.0 kg

The initial temperature of block, T = 50° C

The final temperature of the block, T' = 25° C

The change in temperature, ΔT = 50° C - 25° C

= 25° C

The specific heat capacity of aluminium, c = 900 J/kg°C

The formula for thermal energy,

= 1.0 x 900 x 25

= 22500 J

Hence, the lose of thermal energy is, Q = 22500 J

7 0

3 years ago