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sweet [91]
2 years ago
5

Draw the structure of the major organic product isolated from the reaction of 1-hexyne with sodium amide in liquid ammonia follo

wed by 1-bromobutane.

Chemistry
2 answers:
Gemiola [76]2 years ago
5 0

Answer:

CH3(CH2)3CCH --> CH3(CH2)3CCCH2(CH2)2CH3 + NaBr

Explanation:

This reaction are used in the elongation of a terminal alkyne chain, it can be in 2 steps:

Step 1:

NaNH2 is in this reaction is used in the deprotonation of 1-hexyne to give acetylide ions( RCC-). The ion is an nucleophile because of the lone pair of electrons.

Step 2:

This acetylide ion is a basic ion (because 1-hexyne is a weak acid). The alky halide (1-bromobutane) dissociates to form a primary cation and Br- ion. This cation then attacks the acetylide ion, reacts to form carbon-carbon bonds as well as add to carbonyl.

Below is an attachment for the chemical reaction.

77julia77 [94]2 years ago
3 0

Answer:check explanation and attached file/picture

Explanation:

Alkynes are hydrocarbons and they are very acidic because of hybridization effect(the more acidic the s-character is, the more acidic it is going to be).

The reaction of 1-hexyne with sodium amide in liquid ammonia is a form of deprotonation 'reaction' to form acetylide. Due to the acidic nature of the terminal hydrogen atom, terminal alkynes do form metallic derivatives by the replacement of the terminal hydrogens. The equation of Reaction is given below.

C6H10 + NaNH2( in liquidNH3) ------------> C6H9Na + H-NH2.

The acetylide is a bae and a very good nucleophile.

The reaction is then followed by the addition of 1-bromobutane. This reaction is used for the production of longer chain alkynes. The equation of Reaction is attached in the picture.

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A stable atom that has a large nucleus most likely contains
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Answer:

3. Equal numbers of  protons and neutrons

Explanation:

The nucleus becomes unstable if the ratio of protons to neutrons is less than 1:1 or more than 1:1.5.

The most stable nucleus has a neutron proton ratio of 1:1 which means that they can not release a neutron or a proton to decay.

Nucleus 3 is therefore the most stable.

8 0
3 years ago
A student is taking notes about the four steps in hurricane formation. Which of the following should be written as step number 1
Brrunno [24]
Tropical disturbance is the correct answer
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How many charges do copper(II) and Carbide have
MAVERICK [17]

Answer:

Copper is 2+ and carbide is 2-

5 0
3 years ago
Below is the structure of acetyl chloride, drawn with bonds and electron dots. determine how many nonbonding and bonding electro
erma4kov [3.2K]

Answer : The non-bonding and bonding electrons are 10 and 14 respectively.

Explanation :

Electron-dot structure : It is also known as Lewis-dot structure. It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

The given molecule is, Acetyl chloride (CH_3COCl)

Carbon has '4' valence electrons, hydrogen has '1' valence electron, oxygen has '6' valence electrons and chlorine has '7' valence electrons.

Therefore, the total number of valence electrons in (CH_3COCl) = 2(4) +3(1) +6 +7 = 24

According to electron-dot structure, there are 14 number of bonding electrons ans 10 number of non-bonding electrons.

The electron-dot structure of (CH_3COCl) is shown below.

8 0
2 years ago
Read 2 more answers
I don’t need the answers to this but u can if u want but I’m just asking what is this is asking for and how to solve it? I hope
strojnjashka [21]

Answer:

See explanation

Explanation:

Salts are produced from the reaction of an acid and a base. In general ...

Acid + Base => Salt + Weak Electrolyte

Acids from the 'Arrhenius Definition' contain an 'ionizable' hydrogen (-H). Such as, HCl, HBr, HI, HNO₃, HClO₄, HF, etc.

Bases from the 'Arrhenius Definition' contain an 'ionizable' hydroxide (-OH). Such as, LiOH, NaOH, KOH, CsOH, Ca(OH)₂, etc.

When the acid and base react, they proceed by what is known as a 'Double Replacement Reaction' or 'Metathesis Reaction'. In the process, the ions of the reactant compounds exchange positions such that a 'Driving Force' compound is formed on the product side. The Driving Force compound is <u>always</u> on the product side of the equation and is a compound that takes one of three forms => A precipitating salt, a compound of a weak acid or weak base (weaker than the starting acid or base) or gas decomposition product (~ vinegar + backing soda rxn => CO₂ gas).

For your problem, split the compound into cations and anions. You can usually tell which is which by using this format on formulas like those listed in your question => reading formula from left to right, place an imaginary line after the 1st metal => this metal will be the cation & the remaining formula will be the anion.

KBr => K | Br => K (Potassium) is the cation (K⁺) and Br (Bromide) is the anion (Br⁻)

KBr => K⁺ + Br⁻

Now. Apply this rule => Add 'H' to anion => HBr,  then add 'OH' to cation => KOH.

HBr is the acid and KOH is the base. Therefore ...        

Acid + Base => Salt + Wk Electrolyte

HBr + KOH => KBr + H₂O (note how ions of reactants exchange places to form products).

So, KBr comes from the reaction of acid HBr and base KOH.

HBr + KOH => KBr + H₂O

To determine the acid and base origins of LiCl and NaF, use the same logic. Hope this helps. Doc :-)

7 0
3 years ago
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