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sweet [91]
3 years ago
5

Draw the structure of the major organic product isolated from the reaction of 1-hexyne with sodium amide in liquid ammonia follo

wed by 1-bromobutane.

Chemistry
2 answers:
Gemiola [76]3 years ago
5 0

Answer:

CH3(CH2)3CCH --> CH3(CH2)3CCCH2(CH2)2CH3 + NaBr

Explanation:

This reaction are used in the elongation of a terminal alkyne chain, it can be in 2 steps:

Step 1:

NaNH2 is in this reaction is used in the deprotonation of 1-hexyne to give acetylide ions( RCC-). The ion is an nucleophile because of the lone pair of electrons.

Step 2:

This acetylide ion is a basic ion (because 1-hexyne is a weak acid). The alky halide (1-bromobutane) dissociates to form a primary cation and Br- ion. This cation then attacks the acetylide ion, reacts to form carbon-carbon bonds as well as add to carbonyl.

Below is an attachment for the chemical reaction.

77julia77 [94]3 years ago
3 0

Answer:check explanation and attached file/picture

Explanation:

Alkynes are hydrocarbons and they are very acidic because of hybridization effect(the more acidic the s-character is, the more acidic it is going to be).

The reaction of 1-hexyne with sodium amide in liquid ammonia is a form of deprotonation 'reaction' to form acetylide. Due to the acidic nature of the terminal hydrogen atom, terminal alkynes do form metallic derivatives by the replacement of the terminal hydrogens. The equation of Reaction is given below.

C6H10 + NaNH2( in liquidNH3) ------------> C6H9Na + H-NH2.

The acetylide is a bae and a very good nucleophile.

The reaction is then followed by the addition of 1-bromobutane. This reaction is used for the production of longer chain alkynes. The equation of Reaction is attached in the picture.

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Answer:
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Explanation:
The ionization energy is defined as the energy required to remove electrons from the atoms.
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Based on the above, the atom with the smallest radius would be the atom with the largest first ionization energy.

Hope this help :)
6 0
3 years ago
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For the following reaction, 33.7 grams of bromine are allowed to react with 13.0 grams of chlorine gas.
Ira Lisetskai [31]

Explanation:

The reaction is given as;

Br2(g) + Cl2(g) ----> 2BrCl(g)

From the equation;

1 mol of Br2 reacts with 1 mol of Cl2

Converting the masses given to moles, using the formular;

Number of moles = Mass / Molar mass

Br2;

Number of moles = 33.7 g / 159.808 g/mol = 0.21088 mol

Cl2;

Number of moles = 13.0 g / 70.906 g/mol = 0.18334 mol

From the values;

0.18334 mol of Cl2 would react with 0.18334 mol of Br2 with an excess of 0.02754 mol of Br2

<em>What is the maximum amount of bromine monochloride that can be formed? __________grams</em>

<em />

1 mol of Cl2 produces 2 mol of Bromine Monochloride

0.18334 mol of Cl2 would produce x

Solving for x;

x = 0.18334 * 2 = 0.36668 mol

Converting to mass;

Mass = Number of moles * Molar mass = 0.36668 mol * 115.357 g/mol

Mass = 42.299 g

<em />

<em>What is the FORMULA for the limiting reagent?</em>

<em />

The limiting reagent is Cl2 as it determines the amount of product formed. The moment the reaction uses up Cl2, the reaction stops.

<em>What amount of the excess reagent remains after the reaction is complete? __________grams</em>

The excess reagent is Br2

The number of moles left is;

0.02754 mol of Br2

Converting to mass;

Mass = Number of moles * Molar mass = 0.02754 mol  * 159.808 g/mol

Mass = 4.401 g

7 0
2 years ago
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