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Luba_88 [7]
3 years ago
10

Jimmy's Chemical reaction/ Recipe for making Grilled chese sandwiches is given below: 1 slice of cheese + 2 slices of bread = 1

Grilled chese sandwich ( mole ratio is, 1:2:1) If Jimmy has the following amounts of ingredients (reactants/ reagents) : 10 slices of cheese 30 hslices of bread Answer the questions below in your submission: a) What is the limiting reagent/reactant? b) what is the excess reactant? c) True or false? The number of glilled chese sandwishes he can make is decided by the limiting reactant because it gets used up most.
Chemistry
1 answer:
Juli2301 [7.4K]3 years ago
4 0

Answer:

See explanation

Explanation:

We have been told in the question that the equation of the reaction is; 1 slice of cheese + 2 slices of bread = 1 Grilled cheese sandwich ( mole ratio is, 1:2:1) .

Then the reagents are 10 slices of cheese 30 slices of bread. It then follows that 10 slices of cheese should be combined with 20 slices of bread according to the mole ratio.

However, we have 30 slices of bread and 10 slices of cheese so cheese is the limiting reactant while bread is the reactant in excess.

Yes, the number of glilled chese sandwishes he can make is decided by the limiting reactant because it gets used up most.

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<u>Answer:</u> The change in internal energy of the gas is 29.414 kJ.

<u>Explanation:</u>

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PV=nRT

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We are given:

Conversion used:  1m^3=1000L

P=140kPa\\V=0.23m^3=260L\\n=4.0mol\\R=8.31\text{L kPa }mol^{-1}K^{-1}

Putting values in above equation:

140kPa\times 260L=4mol\times 8.31\text{L kPa }mol^{-1}K^{-1}\times T_i\\\\T_i=1095.06K

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We are given:

P=140kPa\\V=0.12m^3=120L\\n=4.0mol\\R=8.31\text{L kPa }mol^{-1}K^{-1}

Putting values in above equation:

140kPa\times 120L=4mol\times 8.31\text{L kPa }mol^{-1}K^{-1}\times T_f\\\\T_f=505.41K

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\Delta U=nC_v\Delta T=nC_v(T_f-T_i)

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\Delta U = change in internal energy = ?

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T_i = initial temperature = 505.41 K

Putting values in above equation, we get:

\Delta U=4\times \frac{3}{2}\times 8.314J/K.mol\times (505.41-1095.06)\\\\\Delta U=29414.1J

Converting this value in kilojoules, we use the conversion factor:

1 kJ = 1000 J

So, 29414.1J=\frac{1kJ}{1000J}\times 29414.1J=29.414kJ

Hence, the change in internal energy of the gas is 29.414 kJ.

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