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Scorpion4ik [409]
3 years ago
15

For which of the following equilibria does `"K"_("eq") = ["O"_2]`? A. O2(l) O2(g) B. 2O3(g) 3O2(g) C. 2H2O(l) 2H2(g) + O2(g) D.

2Hg(s) +O2(g) 2HgO(s)
Chemistry
2 answers:
Feliz [49]3 years ago
8 0

For plato users

the answer is a. O2(l) O2(g)

hope this helps!

svp [43]3 years ago
3 0

For a hypothetical reaction:

aA ↔ bB

the equilibrium constant is given as:

Keq = [B]^b/[A]^a

activity of pure solids and liquids = 1

For the given reactions:

A) O2(l) ↔ O2(g)

Keq = [O₂]

B) 2O3(g) ↔ 3O2(g)

Keq = [O₂]³/[O₃]²

C) 2H2O(l) ↔2H2(g) + O2(g)

Keq = [H₂]²[O₂]

D) 2Hg(s) + O2(g) ↔ 2HgO(s)

Keq = [Hg]²[O₂]

Ans: A



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Among K, Ca and Ba, which element possess low ionization energy?
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Among the elements Barium has the lowest Ionization Energy.

<h3>What is Ionization Process ?</h3>

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brainly.com/question/6638422

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