I think the answer you have selected is right, I'm not sure tho
Answer:
The answer to your questions is: C. Sulfides
Explanation:
A. Phosphates these compounds do not have sulphur, they are composed by phosphate and oxygen, So this answer is wrong.
B. Sulfates are formed by sulphur and oxygen, not for a metal, then this is not the right answer.
C. Sulfides are molecules formed by a metal and sulphur, this is the anwser to the question.
D. Silicates are formed by sillicon and oxygen, this option is incorrect.
<span>this
could be a substitution reaction. as you will locate, between the
hydrogen's on the propane chain replaced into substituted for a Br from
Br2. that's particularly no longer a addition reaction! addition
reactions artwork once you have a AlkENE! by using fact that's an AlkANE
it would not have a double bond to act as a nucleophile to attack the
Br2 (which might act as a electrophile to boot reactions).</span>
As you move around there is a change in: electronegativies, ionisation energies, atomic radius etc. different amounts of these properties are going to effect how the element acts
Answer:
0.4 M
Explanation:
Equilibrium occurs when the velocity of the formation of the products is equal to the velocity of the formation of the reactants. It can be described by the equilibrium constant, which is the multiplication of the concentration of the products elevated by their coefficients divided by the multiplication of the concentration of the reactants elevated by their coefficients. So, let's do an equilibrium chart for the reaction.
Because there's no O₂ in the beginning, the NO will decompose:
N₂(g) + O₂(g) ⇄ 2NO(g)
0.30 0 0.70 Initial
+x +x -2x Reacts (the stoichiometry is 1:1:2)
0.30+x x 0.70-2x Equilibrium
The equilibrium concentrations are the number of moles divided by the volume (0.250 L):
[N₂] = (0.30 + x)/0.250
[O₂] = x/0.25
[NO] = (0.70 - 2x)/0.250
K = [NO]²/([N₂]*[O₂])
K = 
7.70 = (0.70-2x)²/[(0.30+x)*x]
7.70 = (0.49 - 2.80x + 4x²)/(0.30x + x²)
4x² - 2.80x + 0.49 = 2.31x + 7.70x²
3.7x² + 5.11x - 0.49 = 0
Solving in a graphical calculator (or by Bhaskara's equation), x>0 and x<0.70
x = 0.09 mol
Thus,
[O₂] = 0.09/0.250 = 0.36 M ≅ 0.4 M