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2 years ago

What would you need to do to calculate the molality of 10 mol of NaCl in 200

Chemistry

1 answer:

Makovka662 [10]2 years ago

8 0

It will be the second one

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Which of the following is a physical change. A piece of magnesium metal formed bubbles when dropped in acid

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H2O became a vapor when heated because thats the only one that can go back to its normal state, which is what a physical change is.

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2 years ago

Evidence that best supports the theory of biological evolution was obtained from the

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The homologous structures and the analogous structures of different species.

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2 years ago

134 grams of nitric acid is added to 512 grams of water. Calculate the molality of nitric acid.

Nana76 [90]

Answer: 4.15234 m

512 g H2O * $\frac{1 kg}{1000 g}$ = 0.512 kg H2O

Nitric Acid: HNO3 = 1.008 + 14.007 + 3(15.999) = 63.012 g/mol

H = 1.008 g/mol

N = 14.007 g/mol

O3 = 3*15.999

134 g HNO₃ * $\frac{mol}{63.012 g}$ = 2.126 mol

m = $\frac{2.126 mol}{0.512 kg}$ = 4.15234 m

6 0

3 years ago

Read 2 more answers

92 grams of ethanol,C2H5OH, is dissolved in 1 liter of solution. Determine the molarity (M)

const2013 [10]

Answer: 1.997 M

Explanation:

molarity = moles of solute/liters of solution or $M = \frac{mol}{L}$

first we have to find our moles of solute (mol), which you can find by dividing the mass of solute by molar mass of solute

mass of solute: 92 g

molar mass of solute: 46.08 g/mol

let's plug it in:

$\frac{92 g}{46.08 g/mol} = 1.997 mol$

next, we plug it into our original equation:

$\frac{1.997mol}{1 L} = 1.997 M$

4 0

3 years ago

At a given temperature the vapor pressures of hexane and octane are 183 mmhg and 59.2 mmhg, respectively. Calculate the total va

Bas_tet [7]

Total vapor pressure can be calculated using partial vapor pressures and mole fraction as follows:

$P=X_{A}P_{A}+X_{B}P_{B}$

Here, $X_{A}$ is mole fraction of A, $X_{B}$ is mole fraction of B, $P_{A}$ is partial pressure of A and $P_{B}$ is partial pressure of B.

The mole fraction of A and B are related to each other as follows:

$X_{A}+X_{B}=1$

In this problem, A is hexane and B is octane, mole fraction of hexane is given 0.580 thus, mole fraction of octane can be calculated as follows:

$X_{octane}=1-X_{hexane}=1-0.58=0.42$

Partial pressure of hexane and octane is given 183 mmHg and 59.2 mmHg respectively.

Now, vapor pressure can be calculated as follows:

$P=X_{hexane}P_{hexane}+X_{octane}P_{octane}$

Putting the values,

$P=(0.580)(183 mmHg)+(0.420)(59.2 mmHg)=131 mmHg$

Therefore, total vapor pressure over the solution of hexane and octane is 131 mmHg.

4 0

3 years ago