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3 years ago

5

Explain how to solve for percent ionization.

1 answer:

swat323 years ago

4 0

Percent ionization can be computed by dividing the concentration of H+ in equilibrium by the original concentration of the solution multiplied by 100 percent. The concentration in equilibrium can be determined through the equilibrium constant inherent to the solution itself and upon its complete dissociation

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If more solute can be dissolved in a solvent, the solution is

Mekhanik [1.2K]

Answer: B. Unsaturated

Explanation: in a saturated/super saturated solution, more solute will not be able to dissolve.

8 0

3 years ago

How many potassium atoms are present in 0.01456 g of potassium??

leva [86]

Its going to be 2.81 x 1023 atoms

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3 years ago

What is an Ytterbium (Its an element) . in your own words but be more detailed about what you say.

Butoxors [25]

Answer:

Ytterbium is a chemical element with the symbol Yb and atomic number 70. It is the fourteenth and penultimate element in the lanthanide

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3 years ago

Calculate the % Oxygen in NaHCO3

Alexxx [7]

Answer:

Molar mass of NaHCO3 = 84.00661 g/mo

Explanation:

This compound is also known as Baking Soda or Sodium Bicarbonate.

Convert grams NaHCO3 to moles or moles NaHCO3 to grams

Molecular weight calculation:

22.98977 + 1.00794 + 12.0107 + 15.9994*3

3 0

3 years ago

As a scuba diver descends under water, the pressure increases. At a total air pressure of 2.71 atm and a temperature of 25.0 C,

Semenov [28]

Answer:

$1.32\times 10^{-3} mol/L$ is the solubility of nitrogen gas in a diver's blood.

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_{N_2}=K_H\times p_{liquid}$

where,

$K_H$ = Henry's constant = $6.26 \times 10^{-4}mol/L.atm$

$p_{N_2}$ = partial pressure of nitrogen

$p_{N_2}= P\times \chi_{N_2}$ (Raoult's law)

$=2.71 atm\times 0.78=2.1138 atm$

$C_{N_2}=6.26 \times 10^{-4}mol/L.atm\times 2.1138 atm$

$C_{N_2}=1.32\times 10^{-3} mol/L$

$1.32\times 10^{-3} mol/L$ is the solubility of nitrogen gas in a diver's blood.

3 0

3 years ago