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Debora [2.8K]
3 years ago
5

Explain how to solve for percent ionization.

Chemistry
1 answer:
swat323 years ago
4 0
Percent ionization can be computed by dividing the concentration of H+ in equilibrium by the original concentration of the solution multiplied by 100 percent. The concentration in equilibrium can be determined through the equilibrium constant inherent to the solution itself and upon its complete dissociation
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NH3(g) will take the shape of and completely fill a closed 100.0 milliliter container. 
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Convert 67 inches into a feet
fiasKO [112]

Answer:

Explanation:every feet has 12in so divde, 67/12  so its 5ft 7/12

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__ Cu + ___ HNO₃ → ___ _Cu(NO₃)₂ + ___ NO₂ + ___ H₂O
ivolga24 [154]

Answer:

Cu + 4HNO3 --->   Cu(NO3)2 + 2NO2 + 2H2O.

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3 0
3 years ago
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What is the specific latent heat of fusion of ice if it takes 863 kJ to convert 4.6 kg of ice into water at 0 C?
charle [14.2K]

Answer:

The correct answer is 187.7 J/Jg.

Explanation:

The formula for finding the specific heat of fusion is,  

Specific heat of fusion = Q/m

Here Q is the heat energy added, signified in kJ, and m is the mass of the object in kg.  

Based on the given information, the heat energy added or Q is 869 kJ and the mass of the ice is 4.6 Kg

Now putting the values in the formula we get,  

Specific heat of fusion = Q/m

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5 0
3 years ago
You carefully weigh out 16.00 g of CaCO3 powder and add it to 64.80 g of HCl solution. You notice bubbles as a reaction takes pl
bulgar [2K]

Answer: Mass of CO_2  produced in this reaction was 6.56 grams

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

CaCO_3(s)+2HCl(aq)\rightarrow H_2O(l)+CO_2(g)+CaCl_2(aq)

Mass or reactants =  Mass of CaCO_3+ mass of HCl = 16.00 + 64.80 = 80.80 g

Mass of products  = mass of aqueous solution + mass of CO_2 + = 74.24 + x g

Mass or reactants = Mass of products

80.80 g = 74.24 + x g

x = 6.56 g

Thus mass of CO_2  produced in this reaction was 6.56 grams

7 0
3 years ago
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