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3241004551 [841]
4 years ago
7

A heat engine does 300 J of work during one cycle. In this cycle 900 J of energy is wasted.

Physics
2 answers:
andreyandreev [35.5K]4 years ago
7 0
B, because 300 is 1/3 of 900
zalisa [80]4 years ago
7 0

Answer:

B

Explanation:

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- A capacitor's dielectric material is a vacuum. The capacitor's dielectric constant, or K, will be equal to
dlinn [17]

If  a capacitor's dielectric constant is vacuum its dielectric constant is k will be equal to 1.

<u>Explanation:</u>

Relative permittivity of  a dielectric substance is referred to as its dielectric constant. Relative permittivity/dielectric constant k is a dimensionless quantity that is the ratio of absolute permittivity and vacuum permittivity.

It is given by the expression

k=k=ε /ε0

where ε denotes absolute permittivity and  ε0 denotes permittivity of vacuuum.

Absolute permittivity  ε of vacuum= ε0

therefore k= ε0/ ε0=1

dielectric constant of vacuum is 1 .

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3 years ago
Uan created a chart to help him study for a test.
yuradex [85]

Answer:

Y: transparent objects i think

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3 years ago
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A 4kg block moving right at 6 m/s collides elastically with a 2kg block moving right at 3 m/s find their final velocity
nignag [31]

The final velocity of block 1 is 2.2m/s and the final velocity of block 2 is 3.4m/s.

<h3>What do you mean by elastically?</h3>

Although the terms scalability and elasticity are occasionally used interchangeably, scalability is more commonly used to describe a system's ability to successfully handle an increasing workload, while elasticity implies that the system is also capable of rapidly expanding or decreasing capacity and services. The capacity of an IT environment to grow and shrink in response to business requirements is one of its characteristics. Physics defines resilience as a material's ability to absorb energy and react elastically in order to maintain its integrity and avoid deforming as a result of the pressures it is subjected to.

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6 0
2 years ago
When a surface is illuminated with electromagnetic radiation of wavelength 480 nm, the maximum kinetic energy of the emitted ele
algol [13]

Answer:

Max kinetic energy for 340 nm wavelength will be 2.238\times 10^{-19}j

Explanation:

In first case wavelength of electromagnetic radiation \lambda =480nm=480\times 10^{-9}m

Plank's constant h=6.6\times 10^{-34}J-s

Maximum kinetic energy = 0.54 eV

Energy is given by E=\frac{hc}{\lambda }=\frac{6.6\times 10^{-34}\times 3\times 10^8}{480\times 10^{-9}}=4.125\times 10^{-19}J

We know that energy is given

E=K_{MAX}+\Phi, here \Phi is work function

So 4.125\times 10^{-19}=0.54\times 10^{-19}+\Phi

\Phi =3.585\times 10^{-19}J

Now wavelength of second radiation = 340 nm

So energy E=\frac{hc}{\lambda }=\frac{6.6\times 10^{-34}\times 3\times 10^8}{340\times 10^{-9}}=5.823\times 10^{-19}J

So K_{MAX}=5.823\times 10^{-19}-3.585\times 10^{-19}=2.238\times 10^{-19}j

6 0
4 years ago
A bicyclist of mass 60kg supplies 340W of power while riding into a 5 m/s head wind. The frontal area of the cyclist and bicycle
NikAS [45]

Answer:

87.1 mph

Explanation:

We are given that

Mass,m=60 kg

Power,P=340 W

Speed,v=5 m/s

Area,A=0.344 m^2

Drag coefficient,C_d=0.88

Coefficient of rolling resistance,\mu_r=0.007

Friction force,f=\mu_rmg=0.007\times 60\times 9.8=4.1 N

Where g=9.8 m/s^2

Let speed of cyclist=v'

Drag force,F_d=\frac{1}{2}\rho_{air}AC_dv^2

Density of air,\rho_{air}=1.225 kg/m^3

F_d=\frac{1}{2}\times 1.225\times 0.344\times 0.88(5)^2=4.635N

Power,P=(F_d+f)\times v'

340=(4.1+4.635) v'=8.735v'

v'=\frac{340}{8.735}=38.9m/s

v'=87.1 mph

1 m=0.00062137 miles

1 hour=3600 s

7 0
4 years ago
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