Hey! Here's a a structure of a sample lab report:
<h2>
Summary of Lab <u>
(SUBJECT)</u></h2>
Question(s) we are trying to answer:
<em>Write question(s) here. </em>
<em>Add observations and/or previous experiments. </em>
<em />
<em>HYPOTHESIS</em>
<em />
- <em>prediction</em>
- <em>solution</em>
- <em>replicable proposed solution</em>
- <em>references (in)dependent variable(s)</em>
- <em>etc</em>
<em>MATERIALS</em>
<em />
<em>Make a list of all materials used in the lab. </em>
<em />
<em>PROCEDURE</em>
<em />
Write a detailed, step-by-step list (or paragraph in list format) that explains what you did in the lab.
It should be written so that somebody who's never done this can carry it out. Describe safety concerns.
It helps to have somebody test it out.
Results
Describe what happened!
Should include all data, tables, et cetera.
Label correctly!
Conclusion
Answer the following question:
Do my results support or oppose my hypothesis?
Explain why you chose what you did. Make sure it's UNBIASED.
Discuss errors.
Close out in the end.
Answer:
5 cm
Explanation:
Remember that in the pulley system the rope moves the same distance in both ends of the pulley, what the pulley system does is creating a mechanical advantage which basically means that it takes less effort to pull than the actual effort it would take, so for example if you have to lift a box that is 800 N, with a pulley system and the mechanical advantage you'd have to pull with less force.
You have to know what the temperature of your suroundings first and then you can melt it with the tools you need. yeah that's another thing know what tools you need and then be safe!:D
Answer: 0.258 N
Explanation:
As the density of the object is much less than the density of water, it’s clear that the buoyant force, is greater than the weight of the object, which means that in normal conditions, it would float in water.
So, in order to get the ball submerged in water, we need to add a downward force, that add to the weight, in order to compensate the buoyant force, as follows:
F = Fb – Fg
Fb= δH20* 4/3*π*(d/2)³ * g
Fg = δb* 4/3*π*(d/2)³ *g
F= (δH20- δb) * 4/3*π*(d/2)³*g
Replacing by the values of the densities, and the ball diameter, we finally get:
F= 0.258 N
