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sukhopar [10]
3 years ago
7

The length of a soild of a metallic cube at 20°C is 5•0cm. Given that the linear expansivity of the metal is 4×^-5k^-1. Find the

volume of the cube at 120°C. Find the volume of the cube at 120°C
Physics
1 answer:
tamaranim1 [39]3 years ago
6 0

Answer:

Explanation:

Length of one side of cube = 5 x 10⁻² m .

volume = ( 5 x 10⁻² )³

= 125 x 10⁻⁶ m³

Expression for thermal volume expansion is as follows :

V₂ = V₁ ( 1 + γ Δt )

V₂ and  V₁ are volume before and after rise in temperature , γ is coefficient of volume expansion Δt is increase in temperature .

linear expansivity = 4 x 10⁻⁵ K⁻¹

coefficient of volume expansion γ  = 3 x 4 x 10⁻⁵

= 12 x 10⁻⁵ K⁻¹

Putting the value

V₂ = 125 x 10⁻⁶ ( 1 + 12 x 10⁻⁵ x 100 )

=  125 x 10⁻⁶  +  125 x 10⁻⁶  x 12 x 10⁻³

= 125 x 10⁻⁶  +  1.5  x 10⁻⁶  

= 126.5 x 10⁻⁶

= 126.5 cm³

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To throw the discus, the thrower holds it with a fully outstretched arm. Starting from rest, he begins to turn with a constant a
yawa3891 [41]

Answer:

Explanation:

Time taken to complete one revolution is called time period.

So, Time period, T = 1 s

Diameter = 1.6 mm

radius, r = 0.8 mm

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The relation between angular velocity and the time period is

\omega =\frac{2\pi}{T}

ω = 2 x 3.14 = 6.28 rad/s

The relation between the linear velocity and the angular velocity is

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6 0
3 years ago
What is the weight on mass
Gre4nikov [31]

Answer:

6.39×10^23 kg is the weight on mass

3 0
2 years ago
A thin, circular hoop with a radius of 0.22 m is hanging from its rim on a nail. When pulled to the side and released, the hoop
Alex73 [517]

Answer:

Period of oscillation = 1.33 seconds

Explanation:

The period of oscillation is given by:

T = 2π√[I/(MgL)] 

for I = 2MR² and L = R,

Given: L = 0.22m = R

T = 2π√[2R/g] 

T = 2 × 3.142 Sqrt[( 2 × 0.22)/ 9.8]

T = 6.284 Sqrt(0.44/9.8)

T = 6.284 Sqrt(0.0449)

T = 6.284 × 0.2119

T = 1.33 sec

6 0
3 years ago
Calculate the equivalent resistance for both circuits. Series circuit: 2 Ω and 4 Ω Parallel circuit: 2 Ω and 4 Ω Which circuit h
goldenfox [79]
Equivalent resistance is also known as the overall resistance. 

For resistors in a series circuit, the total resistance is computed using the formula:

R_{T} = R_{1}+ R_{2}+ R_{3}... R_{n}

In other words, you just add up the resistance of each resistor in the series circuit. In your case you only have two resistors. You have 2Ω and 4Ω. So all you need to do is add that up. 

R_{T} = R_{1}+ R_{2}
R_{T} = 2 + 4=6

The total resistance of the series circuit is 6Ω

In a parallel circuit you get the total resistance using the formula:
\frac{1}{R_{T}} = \frac{1}{R_{1}}+\frac{1}{R_{2}}+\frac{1}{R_{3}}...+\frac{1}{R_{n}}

First you get the sum of all fractions and at the end take the reciprocal of the resulting fraction and divide. So let us take your problem into consideration where you have two resistors that have a resistance of 2Ω and 4Ω.

\frac{1}{R_{T}} = \frac{1}{R_{1}}+\frac{1}{R_{2}}
\frac{1}{R_{T}} = \frac{1}{2}+\frac{1}{4}
\frac{1}{R_{T}} = \frac{2}{4}+\frac{1}{4}
\frac{1}{R_{T}} = \frac{3}{4}

Get the reciprocal of the resulting fraction 3/4 and then divide. The reciprocal of 3/4 is 4/3.

4/3 = 1. 33Ω

So if you compare the equivalent resistance of the two circuits, the series circuit has a higher equivalent resistance. 
3 0
3 years ago
Read 2 more answers
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