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3 years ago

Mihuv8tr5qwertgyhjzxcvbnfr5y7nnbvcxzwertgyhujio vv solve the riddle

Engineering

2 answers:

ddd [48]3 years ago

8 0

Answer:

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Explanation:

dixbsnwgdidjwbbwvrjzjsb your welcome(:

Inessa [10]3 years ago

4 0

Answer:

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Explanation:

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Which word from the passage best explains what the web in the passage symbolizes

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Answer:

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3 years ago

. H<br> Kijwhayhwbbwyhwbwbwgwwgbwbwhwh

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3 years ago

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Who was the American founder and leader of the Shakers in the 1770’s who advocated equality, individual responsibility, and peac

DaniilM [7]

Answer: Ann Lee (1736-1784)

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3 years ago

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Water at 15°C is to be discharged from a reservoir at a rate of 18 L/s using two horizontal cast iron pipes connected in series

love history [14]

Answer:

The required pumping head is 1344.55 m and the pumping power is 236.96 kW

Explanation:

The energy equation is equal to:

$\frac{P_{1} }{\gamma } +\frac{V_{1}^{2} }{2g} +z_{1} =\frac{P_{2} }{\gamma } +\frac{V_{2}^{2} }{2g} +z_{2}+h_{i} -h_{pump} , if V_{1} =0,z_{2} =0\\h_{pump} =\frac{V_{2}^{2}}{2} +h_{i}-z_{1}$

For the pipe 1, the flow velocity is:

$V_{1} =\frac{Q}{\frac{\pi D^{2} }{4} }$

Q = 18 L/s = 0.018 m³/s

D = 6 cm = 0.06 m

$V_{1} =\frac{0.018}{\frac{\pi *0.06^{2} }{4} } =6.366m/s$

The Reynold´s number is:

$Re=\frac{\rho *V*D}{u} =\frac{999.1*6.366*0.06}{1.138x10^{-3} } =335339.4$

$\frac{\epsilon }{D} =\frac{0.00026}{0.06} =0.0043$

Using the graph of Moody, I will select the f value at 0.0043 and 335339.4, as 0.02941

The head of pipe 1 is:

$h_{1} =\frac{V_{1}^{2} }{2g} (k_{L}+\frac{fL}{D} )=\frac{6.366^{2} }{2*9.8} *(0.5+\frac{0.0294*20}{0.06} )=21.3m$

For the pipe 2, the flow velocity is:

$V_{2} =\frac{0.018}{\frac{\pi *0.03^{2} }{4} } =25.46m/s$

The Reynold´s number is:

$Re=\frac{\rho *V*D}{u} =\frac{999.1*25.46*0.03}{1.138x10^{-3} } =670573.4$

$\frac{\epsilon }{D} =\frac{0.00026}{0.03} =0.0087$

The head of pipe 1 is:

$h_{2} =\frac{V_{2}^{2} }{2g} (k_{L}+\frac{fL}{D} )=\frac{25.46^{2} }{2*9.8} *(0.5+\frac{0.033*36}{0.03} )=1326.18m$

The total head is:

hi = 1326.18 + 21.3 = 1347.48 m

The required pump head is:

$h_{pump} =\frac{25.46^{2} }{2*9.8} +1347.48-36=1344.55m$

The required pumping power is:

$P=Q\rho *g*h_{pump} =0.018*999.1*9.8*1344.55=236965.16W=236.96kW$

8 0

3 years ago

Consider a standard room thermostat. Determine the sensor, transducer, output, and control stages for this measurement system.

Anni [7]

Answer:

Sensor/transducer: bimetallic thermometer

Output: displacement of thermometer tip

Control Tstages: mercury contact switch (open:furnace off; closed:furnace on

Explanation:

for a standard room thermostat : This is the device that sets/determines the temperature of an enclosure.

Sensor/transducer: bimetallic thermometer: Bimetalic thermometer are used for measuring the temperature of the ambient air . bimetallic thermometer actually contains two metals. they undergo linear expansivity as the temperature of the room changes.in other words, they experience contraction and expansion with increase or decrease in temperature.The sensor is basically coupled with a transducer which turns the measured variable(Temperature) into something else, such as a movement on a dial or an electrical signal

Output: displacement of thermometer tip

Controller: mercury contact switch (open:furnace off; closed:furnace on)

once the contact switch is open the furnace can go off. when the contact switch is closed, the furnace will come up.

3 0

3 years ago