Prevent the release of toxic vapored, dusts, mists, or gases into the workplace air
Answer:
12.8 g of
must be withdrawn from tank
Explanation:
Let's assume
gas inside tank behaves ideally.
According to ideal gas equation- 
where P is pressure of
, V is volume of
, n is number of moles of
, R is gas constant and T is temperature in kelvin scale.
We can also write, 
Here V, T and R are constants.
So,
ratio will also be constant before and after removal of
from tank
Hence, 
Here,
and 
So, 
So, moles of
must be withdrawn = (0.66 - 0.26) mol = 0.40 mol
Molar mass of
= 32 g/mol
So, mass of
must be withdrawn = 
When ΔG° is the change in Gibbs free energy
So according to ΔG° formula:
ΔG° = - R*T*(㏑K)
here when K = [NH3]^2/[N2][H2]^3 = Kc
and Kc = 9
and when T is the temperature in Kelvin = 350 + 273 = 623 K
and R is the universal gas constant = 8.314 1/mol.K
So by substitution in ΔG° formula:
∴ ΔG° = - 8.314 1/ mol.K * 623 K *㏑(9)
= - 4536
A) CH4
In general, methane reactions are difficult to control. Partial oxidation to methanol, for example, is a rather difficult reaction because the chemical reactions that occur continue to form carbon dioxide and water even though the amount of oxygen available is insufficient.
<h2>Further explanation
</h2>
Methane is the simplest hydrocarbon in the form of gas with the chemical formula CH4. Pure methane does not smell, but if used for commercial purposes, a bit of sulfur is usually added to detect leaks that might occur.
Methane is a greenhouse gas. Methane is used in chemical industrial processes and can be transported as frozen liquids (liquefied natural gas, or LNG).
Methane is a major component of natural gas, around 87% of volume.
Methane is not toxic, but is highly flammable and can cause explosions when mixed with air.
Learn More
CH4 / Methane brainly.com/question/9473007
Benefits of methane brainly.com/question/10818009
Details
Class: college
Subject: chemistry
Keywords: ch4, methane, chemicals
C3H8.gas reacts with 5L of O2 at STP