15 is the group that phosphorus is found in.
PH + pOH = 14
12.52 + pOH = 14
pOH = 14 - 12.52
pOH = 1.48
[OH⁻] = 10^ -pOH
[OH⁻] = 10 ^- 1.48
[OH⁻] = 0.033 M
In order to calculate the amount of heat energy required to melt 347 grams of ice, we need to will apply the equation:
Q
= ml, where m is the mass of substance and l is its latent heat of
fusion. For ice, the latent heat of fusion is 334 joules per gram.
Therefore:
Q = 347 x 334
Q = 112,558 joules of energy
Hope this helped.
360 seconds?
i’m guessing that is the answer as the question is unreasonable
3 minutes are left (16-13=3)
