Mg(s) + 2HCl(aq) = H₂(g) + MgCl₂(aq)
v=300 ml=0.3 l
c=4 mol/l
n(HCl)=vc
m(H₂)/M(H₂)=n(HCl)/2
m(H₂)=M(H₂)vc/2
m(H₂)=2.0g/mol·0.3 l · 4mol/l /2 = 1.2 g
1.2 grams of hydrogen gas will be produced
Answer:
t ≈ 235.47 secs
Explanation:
<u>Calculate how long it will take the transformation to go to 88% completion</u>
Given that Avrami equation ( <em>y </em>)= 1 - exp( - kt^n )
n = 2.3
t = 145 secs
reaction = 50% after t = 145 secs
Reaction = 88% after t = ?
attached below is a detailed solution
First you need to calculate the number of moles of aluminium and copper chloride.
number of moles = mass / molecular weight
moles of Al = 512 / 27 = 19 moles
moles of CuCl = 1147 / 99 = 11.6 moles
From the reaction you see that:
if 2 moles of Al will react with 3 moles of CuCl
then 19 moles of Al will react with X moles of CuCl
X = (19 × 3) / 2 = 28.5 moles of CuCl, way more that 11.6 moles of CuCl wich is the quantity you have. So the copper chloride is the limiting reagent.
