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deff fn [24]
3 years ago
14

What is true about the element Francium (Fr, atomic number 87)? choose 3

Chemistry
1 answer:
larisa86 [58]3 years ago
6 0

Answer :

(B) It is likely to form ionic bonds

(D) It is in period seven

(E) It is a metal

Explanation :

Francium is an element whose symbol is 'Fr' and atomic number is 87.

Group 1 alkali metals consists elements Lithium, Sodium, Potassium, Rubidium, Caesium and Francium. Periodic table also shown below.

Francium belongs to the group 1 (alkali metal) and it is in period seven.

It has one valence electron, the electronic configuration of Francium is [Rn} 7s^{1}.

Alkali metals have tendency to form ionic compounds because they have +1 charge.

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pogonyaev

Answer:

a it rarely reach with other elements

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How many Helium atoms are in 12 grams of Helium?
horsena [70]
12gHe/1 × 1molHe/4.0026g × 6.02x10^23atomHe/1mol = 1.8 atoms
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3 years ago
Why has the acidity of the ocean increased over the years?
aalyn [17]

Answer:

I think it's A

Explanation:

Carbon dioxide is added to the atmosphere whenever people burn fossil fuels. ... As the amount of carbon dioxide in the atmosphere rises, the oceans absorb a lot of it. In the ocean, carbon dioxide reacts with seawater to form carbonic acid. This causes the acidity of seawater to increase.

4 0
2 years ago
A balloon containing 0.0400 mol of a gas with a volume of 500 mL was expanded to 1.00 L.
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b

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3 0
2 years ago
Read 2 more answers
1. Marisa determined the melting point of a substance to be 24.5C. Find the percent error of her measurement if the actual melti
USPshnik [31]

Answer:

\%\ Error = 21.5\%

Explanation:

Given

Measured = 24.5

Actual = 31.2

Required

Determine the percentage error

First, we need to determine the difference in the measurement

Difference = |Actual - Measured|

Difference = |31.2 - 24.5|

Difference = |6.7|

Difference = 6.7

The percentage error is calculated as thus:

\%\ Error = \frac{Difference * 100\%}{Actual}

\%\ Error = \frac{6.7 * 100\%}{31.2}

\%\ Error = \frac{670\%}{31.2}

\%\ Error = 21.4743589744\%

\%\ Error = 21.5\% <em>approximated</em>

6 0
3 years ago
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