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Answer:
Value of coefficient of kinetic friction is 0.26 .
Explanation:
Given:
Mass of wooden crate, m = 12.5 kg.
Horizontal force to keep the block moving with constant velocity, F = 32.0 N.
Since, the block is moving with constant velocity.
So, net force experience by it is zero.
Therefore, fore of friction is equal to applied force.
Now, force of friction , ( here
is coefficient of kinetic friction and N is normal force)
Therefore,
Now, both forces are equal.
The value of coefficient of kinetic friction is 0.26 .
Hence, it is the required solution.