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Galina-37 [17]
3 years ago
10

Charge is uniformly distributed throughout a spherical insulating volume of radius R = 4.00 cm. The charge per unit volume is

Physics
1 answer:
Varvara68 [4.7K]3 years ago
8 0

-8.67× 10^6 N/C

The Electric Field is defined as force per unit charge.

E = Q/ 4π£r2

Qv= −6.5 μCm3

Qv = Q/ V= Q/ 4/3 πr3

Hence Q = 4/3 πr3 × Qv

Hence E = 4/3 πr3 × Qv / 4π£r2= Qvr/3£

−6.5 μ × 4/ 3×8.854 ×10^-12

-6.5 × 4 × 10^6/3 = -8.67× 10^6 N/C

Note: £ = 8.854×10^-12m/F

is the permittivity of free space

Qv is the charge per unit volume

V is volume and volume

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Two blocks with different temperatures had entropies of 10 J/K and 30 J/K before they were brought in contact. What can you say
True [87]

Answer:

a. Ssystem  > 40 J/K

Explanation:

Given that

The entropy of first block = 10 J/K

The entropy of second block = 30 J/K

When two bodies come into contact with each other, the entropy of the combined system will increase and the entropy sum remains unchanged: According to the Second law of thermodynamics.The entropy of the system will be greater than 40  J/K.

Therefore the answer is a.

Ssystem  > 40 J/K

6 0
3 years ago
A wave has a wavelength of 13 mm and a frequency of 18 hertz. What is its speed?
labwork [276]
Velocity = Frequency x Wavelength

= 18 x 13 = 234 mm/s
4 0
3 years ago
Explain the uses of Electrophorus <br>​
Maslowich

Answer:

Explanation:

Comment

Interesting creature.

These creatures are the only survivors from an era long past, where nothing else has survived. They are eels capable of discharging a large electrical current. A pack of them (they can hunt in groups) can kill just about anything.

Tribes use and tame them to guard the tribe's tame Electrophorus. They are bread and maintained in schools. While the charge is huge, once discharged, these creatures take a very long time to recharge, so they are not entirely invincible.

8 0
2 years ago
Modeled after the two satellites problem (slide 12 in Lecture13, Universal gravity), imagine now if the period of the satellite
ikadub [295]

Answer:

  R = 6.3456 10⁴  mile

Explanation:

For this exercise we will use Newton's second law where force is gravitational force

      F = m a

The satellite is in a circular orbit therefore the acceleration is centripetal

      a = v² / r

Where the distance is taken from the center of the Earth

     G m M / r² = m v² / r

     G M / r = v²

The speed module is constant, let's use the uniform motion relationships, with the length of the circle is

     d = 2π  r

     v = d / t

The time for a full turn is called period (T)

Let's replace

     G M / r = (2π r / T)²

     r³ = G M T²²2 / 4π²

     r = ∛ (G M T² / 4π²)

We have the magnitudes in several types of units

      T = 88.59 h (3600 s / 1h) = 3.189 10⁵ s

      Re = 6.37 10⁶ m

Let's calculate

     r = ∛ (6.67 10⁻¹¹ 5.98 10²⁴ (3,189 10⁵)²/4π²)

     r = ∛ (1.027487 10²⁴)

     r = 1.0847 10⁸ m

This is the distance from the center of the Earth, the distance you want the surface is

     R = r - Re

     R = 108.47 10⁶ - 6.37 10⁶

     R = 102.1 10⁶ m

Let's reduce to miles

      R = 102.1 10⁶ m (1 mile / 1609 m)

     

      R = 6.3456 10⁴  mile

6 0
3 years ago
In scientific terms, which situation does NOT represent work done on a rock?
Assoli18 [71]
ANSWER: D

EXPLAINATION:

All the other answers are alike so this is the only different one


MARK ME BRAINLIEST PLEASE
7 0
3 years ago
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