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Serga [27]
3 years ago
6

The process by which you group things based on their similarities is known as classifying.

Physics
1 answer:
dusya [7]3 years ago
8 0
True. Classifying by similarities is the basis for biological classification.
You might be interested in
<
goblinko [34]

Answer:

Explanation:

initial velocity u = 32.7 m /s

final velocity v = 50.3 m /s

displacement s = 44500 m

acceleration a = ?

v² = u² + 2 a s

50.3² = 32.7² + 2 x a x 44500

2530.09 = 1069.29 + 89000a

a .016 m /s²

time taken t = ?

v = u + at

50.3 = 32.7 + .016 t

t = 1100 s

6 0
2 years ago
What do we call fixed point around which a lever pivots?
xxTIMURxx [149]
Answer is A) Fulcrum

The fixed point that a lever rotates around is called the fulcrum.
4 0
1 year ago
Read 2 more answers
Suppose that a worker in Freedonia can produce either 6 units of corn or 2 units of wheat per year, and a worker in Sylvania can
Salsk061 [2.6K]

Answer:

a 30 units of corn and 30 units of wheat.

Explanation:

Initially freedonia has 5 workers producing 30 units of of corn (6 units per worker) and another 5 workers producing 10 units of wheat (2 units per worker)

With the trade agreed between the two countries Freedonia can have all of it's 10 workers producing corn, thereby producing 60 units of corn

30 of these are traded for 30 units of wheat therefore allowing the country to consume 30 units of each product.

8 0
3 years ago
Which produces more gravitational force on your textbook: you or the earth?
Yuri [45]
The earth obviously because it is on Earth like we are and it has the same gravital properties. It falls when you drop it and rises when you pick it up
5 0
3 years ago
Water flows through a cast steel pipe (k = 50 W m.K, ε = 0.8) with an outer diameter of 104mm and 2 mm wall thickness. Calculate
masha68 [24]

Answer:

The heat loss per unit length is   \frac{Q}{L}   = 2981 W/m

Explanation:

From the question we are told that

     The outer diameter of the pipe is d = 104mm = \frac{104}{1000} = 0.104 m

     The thickness is  D = 2mm = \frac{2}{1000} = 0.002m  

      The temperature  of water is  T = 90^oC = 90 + 273 = 363K  

      The outside air temperature is T_a = -10^oC = -10 +273 = 263K

        The water side heat transfer coefficient is z_1 = 300 W/ m^2 \cdot K

       The  heat transfer coefficient is  z_2 = 20 W/m^2 \cdot K

The heat lost per unit length is mathematically represented as

           \frac{Q}{L}   = \frac{2 \pi (T - Ta)}{ \frac{ln [\frac{d}{D} ]}{z_1}  +  \frac{ln [\frac{d}{D} ]}{z_2}}

Substituting values

         \frac{Q}{L}   = \frac{2 * 3.142 (363 - 263)}{ \frac{ln [\frac{0.104}{0.002} ]}{300}  +  \frac{ln [\frac{0.104}{0.002} ]}{20}}

           \frac{Q}{L}   = \frac{628}{0.2107}

           \frac{Q}{L}   = 2981 W/m

6 0
3 years ago
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