The process by which you group things based on their similarities is known as classifying.
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In order to get a sample of air that is 23 km above the ground, the rocket must rise by that height.
Draw a diagram (shown below) t represent the problem.
The distance h₁ is traveled from A to B with an upward acceleration of 17 m/s² over 30 s. The distance traveled is
h₁ = (1/2)(17 m/s²)(30 s)² = 7650 m = 7.65 km
At point B, the velocity attained is
V = (17 m/s²)30s) = 510 m/s
The distance h₂ is traveled from B to C with gravitational deceleration of -9.8 m/s². The distance traveled is given by
(510 m/s)² - 2(9.8 m/s²)h₂ = 0
h₂ = 13270.4 m = 13.27 km
The total height attained by the rocket is
h₁ + h₂ = 7.65 + 13.27 = 20.92 km
This height falls short of the desired height of 23 km.
Answer:
The rocket does not travel high enough to sample the air at a height of 23 km.
Draw a diagram (shown below) t represent the problem.
The distance h₁ is traveled from A to B with an upward acceleration of 17 m/s² over 30 s. The distance traveled is
h₁ = (1/2)(17 m/s²)(30 s)² = 7650 m = 7.65 km
At point B, the velocity attained is
V = (17 m/s²)30s) = 510 m/s
The distance h₂ is traveled from B to C with gravitational deceleration of -9.8 m/s². The distance traveled is given by
(510 m/s)² - 2(9.8 m/s²)h₂ = 0
h₂ = 13270.4 m = 13.27 km
The total height attained by the rocket is
h₁ + h₂ = 7.65 + 13.27 = 20.92 km
This height falls short of the desired height of 23 km.
Answer:
The rocket does not travel high enough to sample the air at a height of 23 km.
Answer:
Part a)
Part b)
Part c)
Explanation:
Part a)
When block reached to maximum height then block and ramp will move together.
so here we will have
Part b)
Now we can use energy conservation to find the height
Part c)
When block and ramp separate finally then we have
also by energy equation
by solving above equations we have