1. <span>what is the amount of the bolus dose, in both milligrams and milliliters, that you will administer in the first minute?
</span>The doses is 0.9 mg/kg and the weight of the patient is 143 pounds. So, the total doses of drug needed will be:
Total doses= 0.9 mg/kg * 143 pounds * 0.453592 kg/pound= 58.37 mg.
10% of the doses will be given bolus for 1 min, so the amount would be:
Bolus doses= 10%*58.37 mg= 5.837 mg.
In mililiters, it would be: 5.837 mg * 1ml/mg= 5.837 ml.
<span>2. what is the amount of the remaining dose that you will need to administer?
The remaining dose would be 90% of the total dose. You can either calculate it directly or subtract the bolus doses from the total doses.
Remaining doses= total doses- bolus doses= </span>58.37 mg- 5.837 mg= <span>52.533mg</span>
Answer:
This BclI restriction enzyme recognizes and cut at T / CTAG nucleotide sequences.
Explanation:
5′ CCGCGGT 3′
3′ GGCGCCACTAG 5′
Segment 2
5′ GATCAGGATCC 3′
3′ TCCTAGG 5′
The BclI enzyme generates sticky ends, it means that the enzyme recognises and cuts nucleotide sequences without complementary bases, which also have weak hydrogen bonds. The sticky ends are then generated when an enzyme produces unpaired nucleotide ends. Nonetheless, restriction enzymes generally produce blunt ends, i.e., both strands cut at the same site.
Well since one is newer, it would be more renewable.
The answer is A. Got it right on my end.
