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I am Lyosha [343]

3 years ago

13

Brainliest! Please help me out with this table!! :(

1 answer:

larisa [96]3 years ago

8 0

Protons are always the same as your atomic number.

Mass# - atomic # = neutrons

Atomic# - charge = electrons

To get your mass# you need to add the protons to the neutrons = Mass #

To get the charge look at the difference between the protons and neutrons.

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Elina [12.6K]

H2SO4 + ZN ------- ZNSO4+ H2

(SO4)²The sulphate salt is formed......

Hope it helps

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3 years ago

Fatima is designing an advanced graphics card for a next-generation video game system. She needs to be able to precisely control

belka [17]

Answer:

semiconducting and tellurium

Explanation:

u did the test hope this helps babes

3 0

3 years ago

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A sample of argon gas has a volume of 795 mL at a pres-sure of 1.20 atm and a temperature of 116 ∘C. What is the final volume of

jek_recluse [69]

<u>Answer:</u> The volume when the pressure and temperature has changed is $1.6\times 10^2mL$

<u>Explanation:</u>

To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.

The equation follows:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1,V_1\text{ and }T_1$ are the initial pressure, volume and temperature of the gas

$P_2,V_2\text{ and }T_2$ are the final pressure, volume and temperature of the gas

Let us assume:

$P_1=1.20atm\\V_1=795mL\\T_1=116^oC=[116+273]K=389K\\P_2=0.55atm\\V_2=?mL\\T_2=75^oC=[75+273]K=348K$

Putting values in above equation, we get:

$\frac{1.20atm\times 795mL}{389K}=\frac{0.55atm\times V_2}{348K}\\\\V_2=\frac{1.20\times 795\times 348}{0.55\times 389}=1.6\times 10^3mL$

Hence, the volume when the pressure and temperature has changed is $1.6\times 10^2mL$

5 0

3 years ago

The molar solubility of C a ( O H ) 2 C a ( O H ) 2 was experimentally determined to be 0.019 M. Based on this value, what is th

Anuta_ua [19.1K]

Answer:

Ksp = 2.74 x 10⁻⁵

Explanation:

The solubility equilibrium for Ca(OH)₂ is the following:

Ca(OH)₂(s) ⇄ Ca²⁺(aq) + 2 OH⁻(aq)

I 0 0

C + s + 2s

E s 2s

According to the ICE table, the expression for the solubility product constant (Kps) is:

Ksp = [Ca²⁺] x ([OH⁻])² = s x (2s)² = 4s³

Then, we calculate Ksp from the solubility value (s):

s = 0.019 M

⇒ Ksp = 4s³ = 4 x (0.019)³ = 2.74 x 10⁻⁵

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3 years ago

How many pencils are in 20 OWLS

AVprozaik [17]

Owls means a mammalian species
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4 0

3 years ago

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