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Wittaler [7]
3 years ago
7

Assume a gasoline is isooctane, which has a density of 0.692 g/ml. What is the mass of 3.8 gal of the gasoline (1 gal = 3.78 l)?

Chemistry
1 answer:
sveticcg [70]3 years ago
6 0

Density is the ratio of mass to the volume.

The mathematical expression is given as:

density=\frac{mass}{volume}

Now, density of isooctane = 0.692 g/mL

Volume  = 3.8 gal

Since, 1 gallon = 3.78 L

So, 3.8 gal = 3.78 L\times 3.8

= 14.364 L

As, 1 L = 1000 mL

Therefore, 14.364 L= 14.364 L\times 1000 mL

Volume in mL = 14364 mL

Put the values,

0.692 g/mL=\frac{mass}{14364 mL}

m = 0.692 g/mL\times 14364 mL

= 9939.888 g

Hence, mass of 3.8 gal of the gasoline is 9939.888 g.



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6 0
3 years ago
If the pressure on the surface of water in the liquid stato
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The water will boil at C) 80°C

<h3>Further explanation</h3>

Given

Vapour pressure of water = 47 kPa

Required

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Solution

We can use the Clausius-Clapeyron equation :

\tt ln(\dfrac{P_1}{P_2})=\dfrac{-\Delta H_{vap}}{R}(\dfrac{1}{T_1}-\dfrac{1}{T_2})

Vapour pressure of water at boiling point 100°C=101.325 kPa

ΔH vap for water at 100°C=40657 J/mol

R = 8.314 J/mol K

T₁=boiling point of water at 101.325 kPa = 100+273=373 K

Input given values :

\tt ln\dfrac{101.325}{47}=\dfrac{-40657}{8.314}(\dfrac{1}{373}-\dfrac{1}{T_2})\\\\0.7682=4890.1852(\dfrac{1}{373}-\dfrac{1}{T_2})\\\\0.0001571=(\dfrac{1}{373}-\dfrac{1}{T_2})\\\\\dfrac{1}{T_2}=0.00283\rightarrow T_2=353~K=80^oC

6 0
3 years ago
Scientis often need to define the system under study during an investigation. Explain why defining the system under study is imp
Keith_Richards [23]

Answer:

It is important because it separates the area that the process is happening from its surroundings, and it's easy to measure and make observations by doing that.

Explanation:

The system is the part of the universe that is separated for study. It has a frontier, which is the limitation of it, and the external area is the surroundings.

In the system the chemical and physical process is happening: reactions are taking place, gas is expanding, heat is being absorbed or lost, etc.

So, to understand the process that is happening, it's necessary to define the system under study because the measurements, analyze, and observation will be easily done.

5 0
3 years ago
A student added 50.0 ml of an naoh solution to 100.0 ml of 0.400 m hcl. The solution was then treated with an excess of aqueous
jok3333 [9.3K]

Answer is: concentration of the sodium hydroxide solution is 2M.

Balanced chemical reaction:

3NaOH(aq) + Cr(NO₃)₃(aq) → Cr(OH)₃(s) + 3NaNO₃(aq).

m(Cr(OH)₃) = 2.06 g.

n(Cr(OH)₃) =2.06 g ÷ 103 g/mol.

n(Cr(OH)₃) = 0.02 mol.

From reaction: n(Cr(OH)₃) : n(NaOH) = 1 : 3.

n(NaOH) = 0.06 mol.

From chemical reaction: NaOH(aq) + HCl(aq) → NaCl(aq) + H₂O(l):

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n(NaOH) = 0.06 mol + 0.04 mol = 0.1 mol.

c(NaOH) = 0.1 mol ÷ 0.05 L = 2 mol/L.


7 0
3 years ago
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