How are ionic bonds formed

2 answers:

7 0

Ionic bonds are formed when a cation and an anion transfer electrons. The anion gains electrons from the cation to finish its shell, and is usually a nonmetal or a metalloid. A cation gives the anion its electrons to get rid of its partial shell. Cations are metals.

Vitek1552 [10]3 years ago

5 0

Answer:

Ionic bonds are formed by the transfer of valence electrons (those that can move free) between certain type of atoms, these exchange generates two iconic atoms with opposite charge.

<em>So, basically, the transfer of this electrons is how is formed.</em>

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A 99.8 mL sample of a solution that is 12.0% KI by mass (d: 1.093 g/mL) is added to 96.7 mL of another solution that is 14.0% Pb

andre [41]

Answer:

$m_{PbI_2}=18.2gPbI_2$

Explanation:

Hello,

In this case, we write the reaction again:

$Pb(NO_3)_2(aq) + 2 KI(aq)\rightarrow PbI_2(s) + 2 KNO_3(aq)$

In such a way, the first thing we do is to compute the reacting moles of lead (II) nitrate and potassium iodide, by using the concentration, volumes, densities and molar masses, 331.2 g/mol and 166.0 g/mol respectively:

$n_{Pb(NO_3)_2}=\frac{0.14gPb(NO_3)_2}{1g\ sln}*\frac{1molPb(NO_3)_2}{331.2gPb(NO_3)_2} *\frac{1.134g\ sln}{1mL\ sln} *96.7mL\ sln\\\\n_{Pb(NO_3)_2}=0.04635molPb(NO_3)_2\\\\n_{KI}=\frac{0.12gKI}{1g\ sln}*\frac{1molKI}{166.0gKI} *\frac{1.093g\ sln}{1mL\ sln} *99.8mL\ sln\\\\n_{KI}=0.07885molKI$

Next, as lead (II) nitrate and potassium iodide are in a 1:2 molar ratio, 0.04635 mol of lead (II) nitrate will completely react with the following moles of potassium nitrate:

$0.04635molPb(NO_3)_2*\frac{2molKI}{1molPb(NO_3)_2} =0.0927molKI$

But we only have 0.07885 moles, for that reason KI is the limiting reactant, so we compute the yielded grams of lead (II) iodide, whose molar mass is 461.01 g/mol, by using their 2:1 molar ratio:

$m_{PbI_2}=0.07885molKI*\frac{1molPbI_2}{2molKI} *\frac{461.01gPbI_2}{1molPbI_2} \\\\m_{PbI_2}=18.2gPbI_2$

Best regards.

5 0

3 years ago

Read 2 more answers

Organize the following species in terms

ser-zykov [4K]

Explanation:

F Cl Br

ionization energy decreases we move down the group
so Br<Cl<F

2. Na K Li

ionization energy decreases we move down the group
so K<Na<Li

3. C N O F

ionization energy increases as we move across the peroid
so C<N<O<F

plz mark as brainliest if it helps

6 0

3 years ago

Fe(no3)3 + na0h > fe(oh)3 + nano3 is balanced or unbalanced?

VashaNatasha [74]

Answer:

Unbalanced

Explanation:

$\text{Fe}(\text{NO}_3)}_3+ \text{NaOH} \rightarrow \text{Fe(OH)}_3 + \text{NaNO}_3\\\\\text{Balanced reaction:}\\\\\text{Fe}(\text{NO}_3)}_3+ 3\text{NaOH} \rightarrow \text{Fe(OH)}_3 + 3\text{NaNO}_3$