The pressure increase does not affect the equilibrium shift reaction.
Answer:
D) both groups are equatorial.
Explanation:
To solve this question we can start by drawing the molecule in using the <u>structure of the hexagon</u>. In this structure, we have the methyl group on carbon 1 and the terbutyl group on carbon 3, additionally, if we have a cis structure both groups must have the same type of bond (in this case the wedge bond). (See figure 1)
When we write the <u>chair structure</u>, we must keep the same structure. That is, methyl must be on carbon 1 and terbutyl on carbon 3. Also, the cis configuration must be maintained. With this in mind, we can choose the <u>equatorial configuration</u> for methyl on carbon 1 (since the position equatorial is the one that has <u>less steric impediment and more stability</u>). If this is true for carbon 1, we must place the terbutyl group on carbon 3 in the same configuration (i.e. cis). Therefore, on carbon 3 we must place the tert-butyl down on carbon 3, that is, in the <u>equatorial position</u>. (See figure 1).
Therefore, in the chair-like structure, both groups must be in an equatorial position.
I hope it helps!
Baloon with 3 moles og oxygen at 1 atm.The temperature of the balloon is <u>4 Kelvin</u>.
An ideal gas is a theoretical gas composed of many randomly transferring factor particles that aren't difficult to interparticle interactions. the best gasoline idea is beneficial because it obeys the precise gas law, a simplified equation of country, and is amenable to evaluation under statistical mechanics.
An ideal gas is described as one for which both the extent of molecules and forces between the molecules are so small that they have got no effect at the behavior of the gas. The real gas that acts almost like a really perfect gasoline is helium. that is due to the fact helium, in contrast to maximum gases, exists as an unmarried atom, which makes the van der Waals dispersion forces as low as viable
Using the ideal gas equation:-
Given;
P₁ = 1 atm
V₁ = 100 L
n = 3
r = 8.314
T = PV/nR
= 1 × 100 / 3 × 8.314
= 4 K
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Answer:
Sr, Mg, P, F
Explanation:
The trend for decreasing radii size is up and to the right of the Periodic Table.