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JulijaS [17]
2 years ago
11

How many g are in 3 mol of Iron II Carbonate FeCO3

Chemistry
1 answer:
kozerog [31]2 years ago
4 0

Answer:

348 g FeCO3

Explanation:Use your 3 mol's and find the atomic number of Iron II and CO3 which i think is 115.854 so you multiply it by the 3 and that should give you your grams in FeCO3.

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What is the fate of glucose 6‑phosphate, glycolytic intermediates, and pentose phosphate pathway intermediates in this cell? Gly
madreJ [45]

Answer:

The Phosphorylated  glucose(glucose +inorganic phosphate), with the energy supplied from ATP hydrolysis formed glucose 6- phosphate, which is later converted to 2 molecules of fructose 6-phosphate- this is phosphorylation.And  represented the fate of  glucose -6-phosphate.

The fructose 6-phosphate are converted to triose phosphate- which is a 2-molecules of 3C compound. The latter is oxidized by NAD→ NADH+ to form intermediates in the glycolytic pathways .

These intermediates are converted to ribose 5-phosphates in the presence of transketolase  and transaldolase enzymes.And they are finally   converted to pyruvate in the glycolytic pathway with the production of 2ATPs per molecule of glucose.

Basically the phosphate pathway reaction is very slow due to enzyme catalysis.

3 0
3 years ago
A solution is made by dissolving
nikklg [1K]

Answer:

THE MOLARITY IS 2.22 MOL/DM3

Explanation:

The solution formed was as a result of dissolving 37.5 g of Na2S in 217 g of water

Relative molecular mass of Na2S = ( 23* 2 + 32) = 78 g/mol

Molarity in g/dm3 is the amount of the substance dissolved in 1000 g or 1 L of the solvent. So we have;

37.5 g of Na2S = 217 g of water

( 37.5 * 1000 / 217 ) g = 1000 g of water

So, 172.81 g/dm3 of the solution

So therefore, molarity in mol/dm3 = mol in g/dm3 / molar mass

Molarity = 172.81 g/dm3 / 78 g/mol

Molarity = 2.22 mol/dm3

The molarity of the solution is 2.22 mol/dm3

4 0
3 years ago
describe how a pure dry sample of solid lead carbonate can be obtained from sodium carbonate solution and lead nitrate solution
djyliett [7]

Answer:

Soluble salts can be made by reacting acids with soluble or insoluble reactants. Titration must be used if the reactants are soluble. Insoluble salts are made by precipitation reactions.

Making insoluble salts

An insoluble salt can be prepared by reacting two suitable solutions together to form a precipitate.

Determining suitable solutions

All nitrates and all sodium salts are soluble. This means a given precipitate XY can be produced by mixing together solutions of:

X nitrate

sodium Y

For example, to prepare a precipitate of calcium carbonate:

X = calcium and Y = carbonate

mix calcium nitrate solution and sodium carbonate solution together

calcium nitrate + sodium carbonate → sodium nitrate + calcium carbonate

Ca(NO3)2(aq) + Na2CO3(aq) → 2NaNO3(aq) + CaCO3(s)

It also works if potassium carbonate solution or ammonium carbonate solution is used instead of sodium carbonate solution. Remember that all common potassium and ammonium salts are soluble.

please mark as brainliest

Explanation:

7 0
2 years ago
Which element is reduced in this reaction? 2kmno4 3na2so3 h2o→2mno2 3na2so4 2koh
erik [133]

In a redox chemical reaction, one species gets reduced and another gets oxidized. Manganese element is reduced in this reaction.

<h3>What is oxidized and reduced?</h3>

In a redox reaction, the increase or decrease in the oxidation number and electrons results in the reduction and oxidation of the chemical species. The oxidation and reduction occur simultaneously in a reaction.

The oxidation number of Mn in permanganate ion was +8 on the left side and decreased to +4 on the right side of the equation. Potassium permanganate is an oxidizing agent that has reduced the manganese ion of the permanganate ion.

Therefore, manganese is reduced.

Learn more about reduction and oxidation here:

brainly.com/question/2427143

#SPJ4

3 0
2 years ago
a patient is to receive 25 mg of methimazole, a drug used to treat hyperthyroid conditions. the drug is dissolved in solution co
Rainbow [258]
The drug has a concentration of 6 mg per 1 ml. Therefore, to know that number of ml containing 25 grams, we will simply do cross multiplication as follows:
amount of drug = (25 x 1) / 6 = 4.1667 ml

Therefore, for the patient to receive 25 mg of methimazole, he/she should take 4.1667 ml of the drug solution.
8 0
2 years ago
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