Answer:
Ratio of Vrms of argon to Vrms of hydrogen = 0.316 : 1
Explanation:
The root-mean-square speed measures the average speed of particles in a gas, and is given by the following formula:
Vrms = 
where R is molar gas constant = 8.3145 J/K.mol, T is temperature in kelvin, M is molar mass of gas in Kg/mol
For argon, M = 40/1000 Kg/mol = 0.04 Kg/mol, T = 4T , R = R
Vrms = √(3 * R *4T)/0.04 = √300RT
For hydrogen; M = 1/1000 Kg/mol = 0.001 Kg/mol, T = T, R = R
Vrms = √(3 * R *T)/0.001 = √3000RT
Ratio of Vrms of argon to that of hydrogen = √300RT / √3000RT = 0.316
Ratio of Vrms of argon to that of hydrogen = 0.316 : 1
Answer:
A
Explanation:
I just did this question in class:))
Answer:
The primary n‐butanol health effects identified were developmental and nervous system endpoints. In conducting the literature review and evaluating study findings, the following observations were made: (1) developmental findings were consistently identified; (2) neurodevelopmental findings were inconsistent; (3) evidence for nervous system effects was weak; (4) comparing internal doses from oral and inhalation exposures using physiologically based pharmacokinetic models introduces uncertainties; and (5) a lack of mechanistic information for n‐butanol resulted in the reliance on mechanistic data for ethanol, which may or may not be applicable to n‐butanol.
Explanation:
Answer:
<u><em>100N</em></u>
Explanation:
<u>Given</u> <u>Required</u>
Effort force = 50N Force applied to a resistance = ??
Ideal Mechanical Advantage (IMA) = 2
<u>Solution</u>
Force applied to a resistance = Effort force x Ideal Mechanical Advantage (IMA)
= 50N x 2
= 100N
Answer:
Ka = 4.9 X 10^-9
Explanation:
when the pH is 4.95
the [H+] = 10^-4.95
[H+] = 1.122 e-5
since the equilibrium equation is:
HCN <=> 1 mole H+ & 1 mole CN-
then
[H+] = [CN-]
when
HCN <=> H+ & CN-
Ka = [ H+] [CN-] / [HCN]
Ka = [ 1.122 e-5] [ 1.122 e-5] / [0.255]
Ka = 1.256 e-10 / 0.255
Ka = 4.94 e-9
which rounds off to 2 sig figs into
Ka = 4.9 X 10^-9
======================
p.s. it was the pH pf 4.95 that limited the calculations to 2 sig figs
