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alexandr1967 [171]

3 years ago

13

. The wheel is divided into eight same-sized sections, and three of those sections represent winning a gift certificate. Assumin

g the wheel is fair, approximately how many gift certificates are likely to be won if 528 customers spin the wheel

1 answer:

aivan3 [116]3 years ago

3 0

<h3>Answer: 198</h3>

The probability of winning is 3/8 since there are 3 winning spaces out of 8 total.

We expect to have (3/8)*528 = 198 winners

Note how if we had 198 winners out of 528 total players, then the empirical probability of winning is 198/528 = 3/8

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Please help me with this

yan [13]

ANSWER: 127

The shape has 5 sides so it’s inner angles add to 540°.
from this you can add up the angles shown on the diagram and subtract this from 540
the answer this gives you is 127 :)

6 0

2 years ago

Read 2 more answers

What is the area of a circle with a radius of 6 inches? (Leave your answer in terms of Pi. This means: do not multiple by 3.14,

pickupchik [31]

Answer:

36π in^2

Step-by-step explanation:

Area of a circle = π(6)^2 = 36π

6 0

2 years ago

Let f(x) = 1/x^2 (a) Use the definition of the derivatve to find f'(x). (b) Find the equation of the tangent line at x=2

Verdich [7]

Answer:

(a) $f'(x)=-\frac{2}{x^3}$

(b) $y=-0.25x+0.75$

Step-by-step explanation:

The given function is

$f(x)=\frac{1}{x^2}$ .... (1)

According to the first principle of the derivative,

$f'(x)=lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{\frac{1}{(x+h)^2}-\frac{1}{x^2}}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{\frac{x^2-(x+h)^2}{x^2(x+h)^2}}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{x^2-x^2-2xh-h^2}{hx^2(x+h)^2}$

$f'(x)=lim_{h\rightarrow 0}\frac{-2xh-h^2}{hx^2(x+h)^2}$

$f'(x)=lim_{h\rightarrow 0}\frac{-h(2x+h)}{hx^2(x+h)^2}$

Cancel out common factors.

$f'(x)=lim_{h\rightarrow 0}\frac{-(2x+h)}{x^2(x+h)^2}$

By applying limit, we get

$f'(x)=\frac{-(2x+0)}{x^2(x+0)^2}$

$f'(x)=\frac{-2x)}{x^4}$

$f'(x)=\frac{-2)}{x^3}$ .... (2)

Therefore $f'(x)=-\frac{2}{x^3}$ .

(b)

Put x=2, to find the y-coordinate of point of tangency.

$f(x)=\frac{1}{2^2}=\frac{1}{4}=0.25$

The coordinates of point of tangency are (2,0.25).

The slope of tangent at x=2 is

$m=(\frac{dy}{dx})_{x=2}=f'(x)_{x=2}$

Substitute x=2 in equation 2.

$f'(2)=\frac{-2}{(2)^3}=\frac{-2}{8}=\frac{-1}{4}=-0.25$

The slope of the tangent line at x=2 is -0.25.

The slope of tangent is -0.25 and the tangent passes through the point (2,0.25).

Using point slope form the equation of tangent is

$y-y_1=m(x-x_1)$

$y-0.25=-0.25(x-2)$

$y-0.25=-0.25x+0.5$

$y=-0.25x+0.5+0.25$

$y=-0.25x+0.75$

Therefore the equation of the tangent line at x=2 is y=-0.25x+0.75.

5 0

3 years ago

21. The area of a triangle with a base of 12<br> cm and a height of 9.6 cm

Nastasia [14]

The equation for area of a triangle is A= 1/2bh so a=1/2(12cm)(9.6cm)

4 0

2 years ago

Write the simplified form of -64^1/3

GREYUIT [131]

Answer:

-4

Step-by-step explanation:

<em>Factor by the numbers from left to right.</em>

<em> $64^\frac{1}{3}$ </em>

<em> $64=4^3$ </em>

<em> $(\frac{4}{3})^\frac{1}{3}=4^3^*^\frac{1}{3}=4$ </em>

<em>It changes to positive to negative.</em>

<em>-4</em>

<em>-4 is the correct answer.</em>

8 0

3 years ago