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Aleonysh [2.5K]
3 years ago
6

Can someone answer the bottom question (22-25)

Chemistry
1 answer:
Sindrei [870]3 years ago
8 0
22) Oxygen with a -2 charge
23) Neon with a +2 charge
24) Fluorine with a -1 charge
25) Lithium with a +1 charge
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Answer:

Electrical energy = 130000000 J and Heat energy = 520000000 J

Explanation:

Multiply the amount of joules from the last question (650000000) by .20 and .80. (Which are the percentages)

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2 years ago
The autoignition of both ethanol and octane occurs at 363 oC. Which gas sample contains the gas molecules that have a greater av
USPshnik [31]

Answer:

See explanation

Explanation:

At the same temperature, the average kinetic energy of gases depends on the molecular mass of the gas. Hence,  given a particular temperature, lighter molecules travel faster on the average than heavier molecules.

Considering ethanol and octane, The molar mass of ethanol is 46.07 g/mol while the molar mass of octane is 114.23 g/mol. Hence, ethanol has a greater average kinetic energy than octane at the same temperature.

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3 years ago
A kilobyte is 210. A megabyte is 220 bytes. How many kilobytes are in a megabyte? Use the exponent rule for division to find you
Sedaia [141]
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8 0
2 years ago
Read 2 more answers
If 6. 000 g of sugar is mixed with 9. 000 g of water, what is the concentration in weight percent?.
lbvjy [14]

The concentration in weight percent when 6 g of sugar is mixed with 9 g of water is 40%.

There are several ways to denote the concentration of a solution like

  • Molarity
  • Molality
  • Mass percent
  • Mole Fraction

The formula for calculating mass percent is as follows

Mass per cent = (Mass of solute/Mass of solute + Mass of solvent) x 100%

In the given situation sugar is the solute and water is the solvent.

Putting the given values in the above formula

Mass per cent = (6/6+9) x 100%= 6/15 x 100% = 40%

Hence, the concentration in weight percent when 6 g of sugar is mixed with 9 g of water is 40%.

To know more about "concentration of a solution", refer to the link given below:

brainly.com/question/26579666?referrer=searchResults

#SPJ4

7 0
9 months ago
A 2.350×10−2 M solution of NaCl in water is at 20.0∘C. The sample was created by dissolving a sample of NaCl in water and then b
sveta [45]

Answer:

  • Part A: m = 0.02356 mol/kg = 0.02356 m
  • Part B: Xsolute = 4.243×10⁻⁴
  • Part C: % m/m = 0.1376%
  • Part D: ppm = 1,376 ppm

Explanation:

<u>1. Data:</u>

a) M = 2.350×10⁻² M

b) V sol = 1.000 L

c) V H₂O = 994.4 mL = 0.9944 L

d) d H₂O = 0.9982 g/mL

<u>2. Formulae</u>

  • M = n solute / V sol (L)
  • m = n solute / Kg solvent
  • X solute = n solute / N total
  • % m/m = (mass of solute / mass of solution) × 100
  • ppm = (mass of solute / mass of solution) × 1,000,000
  • density = mass in grams / volume in mL

<u>3. Solution</u>

<u>Part A: Calculate the molality of the salt solution. </u>

<u />

            m = n solute / Kg solvent

i) M = n solute / V sol (L) ⇒ n solute = M × V sol (L)

⇒ n solute = M = 2.350×10⁻² M × 1.000 L = M = 2.350×10⁻² mol

ii) density H₂O = mass H₂O / volume H₂O

⇒ mass H₂O = density H₂O × volume H₂O

⇒ mass H₂O = 0.9982 g/mL × 999.4 mL = 997.6 g

iii) kg  H₂O = 997.6 g / (1,000 g/Kg) = 0.9976 kg

iv) m = 2.350×10⁻² mol / 0.9976 kg = 0.02356 mol/kg = 0.02356 m

<u>Part B: Calculate the mole fraction of salt in this solution</u>.

          X solute = n solute / N total

i) n solute =  2.350×10⁻² mol

ii) n solvent = n H₂O = mass H₂O in grams/ molar mass H₂O

⇒ 997.6 g / 18.015 g/mol = 55.38 mol

iii) X solute = 2.350×10⁻² mol / 55.38 mol = 4.243×10⁻⁴

<u>Part C: Calculate the concentration of the salt solution in percent by mass</u>.

         % m/m = (mass of solute / mass of solution) × 100

i) molar mass = mass in grams / molar mass

⇒ mass of solute = mass of NaCl = n solute × molar mass NaCl

⇒ mass of solute = 2.350×10⁻² mol × 58.44 g/mol = 1.373 g

ii) % m/m = (1.373 g / 997.6 g) × 100 = 0.1376%

Part D: Calculate the concentration of the salt solution in parts per million.

       ppm = (mass of solute / mass of solution) × 1,000,000

i) ppm = ( (1.373 g / 997.6 g) × 1,000,000 = 1,376 ppm

5 0
3 years ago
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