To determine the upper bond
Ec(u) = EmVm + EpVp
Em is the elastic modulus of cobalt.
E₁ is the elastic modulus of the particulate
Vm is the volume fraction of cobalt
Vp is the volume fraction of particulate
substitute
Ec(u) = 200 (Vm) + 700 (Vp)
To determine the lower bound
Ec (l) = EmEp/VmEp+ VpEm
Substitute
Ec (l) = 200(700)/Vm(700) + Vp (200)
Ec (l) = 1400/7Vm+2Vp
Answer: 15.3 grams C
Explanation: 1 mole is 6.02x10^23 atoms. We can find the moles of C in 7.675 x 10^23 atoms of C by dividing:
(7.675 x 10^23 atoms C)/(6.02x10^23 atoms C/mole) = 1.275 moles C
The molar mass of carbon is 12g/mole. So the mass of 7.675 x 10^23 atoms is (1.275 moles C)*(12 g/mole C) = 15.3 grams.
Answer:
Condensation and Depositon
Explanation:
Condensation is from gas to liquid
Deposition is from gas to solid
Answer:
53.29%
Explanation:
The molar mass of C2H4O2 is 60.05g and the 2 O's are 32.00g
so 32.00/60.05= 0.53288925895
and that as a decimal rounded to the nearest hundredths is 53.29%
It is in Group 3A = 3 valence electrons
Electron Config. = 1s2 2s2 2p6 3s2 3p1
