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bekas [8.4K]
3 years ago
15

Please help (30 points)

Chemistry
2 answers:
aleksandrvk [35]3 years ago
7 0

1) is chemical Bonds

3) Conservation of mass

5) compound

hope i helped on the ones i could answer

stellarik [79]3 years ago
6 0
All I know is 1. Chemical Bond
You might be interested in
Help me please!!!!!!!!!!!!!!!
Alex787 [66]

Answer:

2KBr + MgF₂ –> 2KF + MgBr₂

The coefficients are: 2, 1, 2, 1

Explanation:

KBr + MgF₂ –> KF + MgBr₂

The above equation can be balance as illustrated below:

KBr + MgF₂ –> KF + MgBr₂

There are 2 atoms of F on the left side and 1 atom on the right. It can be balance by writing 2 before KF as shown below:

KBr + MgF₂ –> 2KF + MgBr₂

There 2 atoms of K on the right side and 1 atom on the left side. It can be balance by writing 2 before KBr as shown below:

2KBr + MgF₂ –> 2KF + MgBr₂

Now, the equation is balanced.

The coefficients are: 2, 1, 2, 1

8 0
3 years ago
Complete the table and sort the wavelengths
suter [353]

Answer:

Energy: Radio Waves least, Infrared 2nd,, Blue light 3rd, Gamma Rays 4th

Wavelength: Gamma Rays smallest wavelength, Blue light 2nd, Infrared 3rd, Radio waves 4th

Frequency: Radio Waves smallest frequency, Infrared 2nd, Blue Light 3rd, Gamma Rays 4th

Explanation:

The different types of radiation are defined by the the amount of energy found in the photons. Radio waves have photons with low energies, microwave photons have a little more energy than radio waves, infrared photons have still more, then visible, ultraviolet, X-rays, and, the most energetic of all, gamma-rays.

5 0
3 years ago
When 50.0 g of 0.200 M NaCl(aq) at 24.1 °C is added to 100.0 g of 0.100 M AgNO3(aq) at 24.1 °C in a calorimeter, the temperature
Annette [7]

Answer:

Q = 693 J

Explanation:

NaCl (aq) + AgNO₃ (aq) → AgCl (s) + NaNO₃ (aq)

Q = mcΔT

Q: heat

m: mass

c: specific heat

ΔT: temperature variation

Q = (50.0g + 100.0g) x (4.20 J/g°C) x (25.2°C - 24.1°C)

Q = 693 J

4 0
3 years ago
A chemistry lab needs to make 100 gallons of an 18% acid solution by mixing a 12% acid solution with a 20% solution. find the nu
Dominik [7]
The question above can be answered by using the volume balance concept. Two equations can be established by total volume balance and the component (acid) volume balance.

If we let x be the volume of the 12% acid solution, the volume of the 20% acid solution will have to be 100 - x.

                 x + (100 - x) = 100

Then, the acid mass balance will give us the equation,

     (x)(0.12) + (100 - x)(0.20) = (100)(0.18)

Simplifying,
     0.12x + 20 - 0.20x = 18
             -0.08x = 20 - 18 
               -0.08x = 2

The value of x from the equation is 25.

<em>Hence, the volume of the 12% acid solution is 20 galloons and that of the 20% acid solution is 75 galloons. </em>
5 0
3 years ago
Read 2 more answers
A chemical engineer must calculate the maximum safe operating temperature of a high-pressure gas reaction vessel. The vessel is
RUDIKE [14]

Answer:

523°C

Explanation:

Step 1:

Data obtained from the question.

Diameter (d) = 31.0 cm

Height (h) = 37.2 cm

Pressure (P) = 5.90 MPa

Mass of ClF5 = 3.27 kg

Temperature (T) =?

Step 2:

Determination of the volume of the stainless-steel cylinder.

Volume of cylinder = πr^2h = π/4d^2h

V = π/4 x (31)^2 x 37.2

V = 28077.36 cm3

Converting the volume to L, we have:

1 cm3 = 0.001 L

Therefore, 28077.36 cm3 = 28077.36 x 0.001 = 28.07736 L

Step 3:

Conversion of 5.90 MPa to atm.

1 MPa = 9.869 atm

Therefore, 5.90 MPa = 5.90 x 9.869

= 58.2271 atm

Step 4:

Determination of the number of mole of chiorine pentafluoride gas (ClF5). This is illustrated below:

Molar Mass of ClF5 = 35.5 + (19x5) = 35.5 + 95 = 130.5g/mol

Mass of ClF5 = 3.27kg =3.27x10000

Mass of ClF5 = 3270g

Number of mole = Mass /Molar Mass

Number of mole of ClF5 = 3270/130.5

Number of mole of ClF5 = 25.057 moles

Step 5:

Determination of the temperature.

Applying the ideal gas equation

PV = nRT, the temperature T, can be obtained as follow:

P = 58.2271 atm

V = 28.07736 L

n = 25.057 moles

R (gas constant) = 0.082atm.L/Kmol

T=?

PV = nRT

Divide both side by nR

T = PV /nR

T = (58.2271x28.07736)/(25.057x0.082)

T = 795.68 K

Step 6:

Conversion of Kelvin temperature to celsius temperature.

°C = K - 273

K = 795.68 K

°C = 795.68 - 273

°C = 523°C

Therefore, the maximum safe operating temperature the engineer should recommend is 523°C

5 0
3 years ago
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