<span>a)
</span>First order
in A and zero order in B
<span>ln [A]
= (ln 0.1) (2) + ln Ao = ln 0.01 + ln Ao = ln 0.01 Ao = 1.0% of A will remain</span>
<span>b)
</span>First
order in A and first order in B
<span>1/[A] – 1/[A]0= kt where t+=1 and k=9</span>
[A]/[A]=1/19=0.053=5.3%
<span>c)
</span>Zero
order in both A and B
<span>[A]0-[A] = kt</span>
Then at 2
hours [A]=0 All of it has reacted.
<span> </span>
Answer:
The answer to your question is letter E. 288.4 g/mol
Explanation:
Data
Number of carbons = 19
mass percent of carbon = 79.12
molar mass = ?
Process
1.- Calculate the molar mass of 19 atoms of carbon
Atomic mass of carbon = 12 g
Atomic mass of 19 atoms of carbon = 228 g
2.- Use proportions to calculate the mass of testosterone
228 g --------------- 79.12 %
x -------------- 100 %
x = (228 x 100) / 79.12
Simplify
x = 22800 / 79.12
Molar mass of testosterone = 288.2 g
<span>Which of the following lists characteristics of a lake and NOT a reservoir A. Artificial dam, fresh water B. natural dam, filled by runoff C. earth dam, salt water D. filled by erosion, cement dam
Answer is B: natural dam,filled by runoff</span>
Answer:
Answers are in the explanation
Explanation:
Based on the reaction:
CF₄ + 2Br₂ → CBr₄ + 2F₂
The mole ratio of CF₄ is:
CF₄:Br₂ = 1:2
CF₄:CBr₄ = 1:1
CF₄:F₂ = 1:2
<em>Moles F2:</em>
Molar mass CF₄: 88.0g/mol
57.0g * (1mol / 88.0g) = 0.6477 moles CF₄ * (2mol F₂ / 1mol CBr₄) =
<h3>1.30 moles F₂</h3><h3 />
<em>Mass Br2:</em>
Molar mass CBr₄: 331.63g/mol
250.0g * (1mol / 331.63g) = 0.7539 moles CBr₄ * (2mol Br₂ / 1mol CF₄) =
1.51 moles Br₂ * (159.808g / mol) =
<h3>241g Br2</h3><h3 /><h3 />
<em>Moles F2:</em>
4.8 moles CF₄ * (2mol F₂ / 1mol CF₄) =
<h3>9.6 moles F₂</h3><h3 />
<em />
Yes
Methane also is the chief constituent of natural gas, which contains from 50 to 90 percent methane (depending on the source), and occurs as a component of firedamp (flammable gas) along coal seams.
