Pls help, easy geometry question

Mathematics

2 answers:

Lemur [1.5K]3 years ago

3 0

x^2 + y^2 + 2x - 6y + 1 = 0

x^2 +2x + 1 + y^2 - 6y = 0

x^2 + 2( x × 1) + 1^2 + y^2 - 2(y×3) + 3^2 -3^2 =0

(x+1)^2 + (y-3)^2 = 3^2

comparing with circle equation

(x-a)^2 + (y - b)^2 = r^2

where (a , b) is centre of circle.

so we get center of circle is

(-1, 3)

malfutka [58]3 years ago

3 0

Answer:

x²+y²+2x -6y + 1 = 0

x² +2x + 1 + y² - 6y = 0

x² + 2( x × 1) + 1² + y² - 2(y×3) + 3² -3² =0

(x+1)² + (y-3)² = 3²

The circle equation is:

(x-a)² + (y - b)² = r²

(a , b) = centre of circle.

So the centre of the circle is

<u>(-1, 3)</u>

Step-by-step explanation:

You might be interested in

A shopper bought shoes 45.00. the sales tax is 65%. How much did the shopper pay in all

Yuri [45]

45*65= 29.45
29>45= 74.25

3 0

3 years ago

describe the transformations that produce the graph of g(x)=1/2(x-4)^3+5 from the graph of the parent function f(x)=x^3. Give th

SSSSS [86.1K]

We have been given a parent function $f(x)=x^{3}$ and we need to transform this function into $g(x)=\frac{1}{2}(x-4)^{3}+5$ .

We will be required to use three transformations to obtain the required function from $f(x)=x^{3}$ .

First transformation would be to shift the graph to the right by 4 units. Upon using this transformation, the function will change to $g(x)=(x-4)^{3}$ .

Second transformation would be to compress the graph vertically by half. Upon using the second transformation, the new function becomes $g(x)=\frac{1}{2}(x-4)^{3}$ .

Third transformation would be to shift the graph upwards by 5 units. Upon using this last transformation, we get the new function as $g(x)=\frac{1}{2}(x-4)^{3}+5$ .

6 0

4 years ago

Tash 3 write the Following in expanded form then in word form. 1. 355,645

Karolina [17]

Answer:

u will get a option like this when u put ur question then u can add photos!!