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elena-s [515]
3 years ago
13

Mechanical (sound) waves are unable to travel through a vacuum, such as through space, but radio waves are transmitted to earth

from satellites. how is this possible?a)radio waves are electromagnetic waves.b)satellites are located within our atmosphere.c)radio waves are very high energy mechanical waves.d)radio waves are changed to gamma rays for transmission.
Physics
1 answer:
Hitman42 [59]3 years ago
7 0
The answer is C radio waves are very high energy mechanical waves.
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A battery is a device that stores chemical energy and converts it to electrical energy. Two terminals made of different chemicals (typically metals), the anode and the cathode; and the electrolyte, which separates these terminals.
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Ground reaction force acting on carter
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8 0
3 years ago
a blackbody is at temperature of 500°C . What would be its temperature in Kelvin for it to radiate twice as much energy per seco
Firdavs [7]

Answer:

773.15K

Explanation:

Temperature is measured in different units, however, the standard or absolute temperature unit is Kelvin (K).

To convert the temperature of a black body, which is 500°C to Kelvin, we use;

T(K) = T(°C) + 273.15

T(K) = 500°C + 273.15

T(K) = 773.15K

Hence, the temperature of the blackbody at 500°C will be 773.15 K for it to radiate twice as much energy per second.

3 0
3 years ago
Which of the following keys moves the insertion point to the beginning of data in a cell? (Points : 2)
Korvikt [17]
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6 0
3 years ago
A baseball is thrown at an angle of 25 degrees relative to the ground at a speed of 23 m/s. If the ball was caught 42 m from the
ExtremeBDS [4]

Answer:

a) v_{0y} = 9.72 m/s

b) v_{0x} = 20.85 m/s

c) t = 2.01 s

d) h_{max} = 4.82 m

Explanation:

a) The initial vertical velocity is given by:

v_{0y} = v*sin(\theta)

Where:

θ: 25°

v: is the magnitude of the speed = 23 m/s

v_{0y} = 23 m/s*sin(25) = 9.72 m/s

b) The initial horizontal velocity can be calculated as follows:

v_{0x} = v*cos(\theta) = 23 m/s*cos(25) = 20.85 m/s

c) The flight time can be calculated using the following equation:

v_{0x} = \frac{x}{t}

Where:

x: is the total distance = 42 m

t = \frac{x}{v_{0x}} = \frac{42 m}{20.85 m/s} = 2.01 s

d) The maximum height is given by:

v_{fy}^{2} = v_{0y}^{2} - 2gh_{max}

Where:

v_{fy}: is the final vertical velocity =0 (at the maximum heigth)

g: is the gravity = 9.81 m/s²

h_{max} = \frac{v_{0y}^{2}}{2g} = \frac{(9.72 m/s)^{2}}{2*9.81 m/s^{2}} = 4.82 m

I hope it helps you!                                  

7 0
3 years ago
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