Question

a blackbody is at temperature of 500°C . What would be its temperature in Kelvin for it to radiate twice as much energy per second?​

Answer 1

Answer:

773.15K

Explanation:

Temperature is measured in different units, however, the standard or absolute temperature unit is Kelvin (K).

To convert the temperature of a black body, which is 500°C to Kelvin, we use;

T(K) = T(°C) + 273.15

T(K) = 500°C + 273.15

T(K) = 773.15K

Hence, the temperature of the blackbody at 500°C will be 773.15 K for it to radiate twice as much energy per second.