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Sliva [168]
3 years ago
9

Whats 3/4 of 12 cause its a hard problem fir .e

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
5 0
3/4 x 12 = 9. 3/4 is the same thing as .75 . 12 x .75 = 9
Naya [18.7K]3 years ago
4 0
Put this in your calculator or use pictures if you'd like. (3/4) x 12 and you'll get 9

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Thanks has a piece of rope that is 6 2/3 feet long how do you write 6 2/3 of a fraction greater than 1
icang [17]

Answer: 20/3

Step-by-step explanation: 3*6=18+2=20

8 0
4 years ago
Graph the line that passes through the points (8,0) and (2,6) and determine the
pantera1 [17]

Answer:

y= -x+ 8

Step-by-step explanation:

4 0
3 years ago
I don’t understand it
Alisiya [41]

Let's deal with each factor in the numerator individually first: when evaluating the power of a power, you have to multiply the exponents: (a^b)^c = a^{bc}

So, we have

[tex](3^2)^{-\frac{1}{2}} = 3^{2\cdot(-\frac{1}{2})} = 3^{-1},\quad (9^4)^{-1} = 9^{-4}

Now remember that 9=3^2 and 27=3^3 to rewrite the expression as

\dfrac{3^{-1}\cdot (3^2)^{-4}}{(3^3)^{-3}} = \dfrac{3^{-1}\cdot 3^{-8}}{3^{-9}}

Now use the rules

a^b\cdot a^c = a^{b+c},\quad \dfrac{a^b}{a^c} = a^{b-c}

to conclude

\dfrac{3^{-1}\cdot 3^{-8}}{3^{-9}} = 3^{-1-8-(-9) = 3^0 = 1

7 0
3 years ago
Which other parts must be equal for triangle ABC= triangle MTR by
lesya692 [45]

Answer:

see below

Step-by-step explanation:

ASA stands for <u>Angle</u><u>-side-Angle</u>

thus, for ∆ABC\cong∆MTR

\displaystyle  \angle C  \cong  \angle R

SAS stands for <u>Side-angle-Side </u>

thus,for ∆ABC\cong∆MTR

\displaystyle \overline{  MR }\cong  \overline{MT}

likewise,

AAS stands for <u>Angle-Angle-Side</u>

thus,for ∆ABC\cong∆MTR

\displaystyle  \angle M \cong \angle T

7 0
3 years ago
Solve the equation.<br> 2/3-4x+7/2=-9x+5/6
Alik [6]

Answer:

x=-2/3

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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