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Rom4ik [11]
3 years ago
13

Sodium chloride is an example of a

Chemistry
2 answers:
Andrei [34K]3 years ago
6 0
C. Weak acid is the correct answer
elena-14-01-66 [18.8K]3 years ago
5 0
It’s a strong electrolyte. Electrolytes are ions in aqueous solution, and sodium and chlorine are both ions in NaCl.
You might be interested in
Which two elements have similar physical and chemical properties?
guapka [62]

Explanation:

Elements in the same group have same number of valence electrons. And we know, the elements which have same number of valence electrons, have similar physical and chemical properties. Hence, the elements in the same group have similar physical and chemical properties.

5 0
3 years ago
Sophia was fascinated while studying the role of oceans in the hydrosphere. She decided to illustrate the features of the ocean
ANEK [815]

Answer:

The Major features of the ocean floor are:

  1. Continental Shelf
  2. Continental Slope
  3. Continental Rise
  4. Abyssal Plain
  5. Oceanic Trench
  6. Mid-Ocean Ridge

Explanation:

1. Continental Shelf: This refers to the part of the land on every continent that is covered with water that is not too deep. The types of animals that can be found on the continental shelf are:

Crab, Tuna, Lobster, Dungeness cod, etc. Within the Continental shelf, there are permanent rocks that house other organisms such as sponges, anemones, clams, sponges, oysters. The continental shelf also contains the route of migration for bigger animals such as sea turtles dolphins and even whales.

2. Continental Slope: This spans from the shelf break to the continental rise.  It can slope up to 4 degrees. Slopes can be created by faulting, slumping of huge boulders of sediments, rifting, etc.

Some of the aquatic animals that can be found in this region include but are not limited to:

Sablefish, Dover sole rockfish, etc.

3. Continental rise

This part of the ocean floor usually has a very steep gradient or angle slope. It slopes very steeply into the abyssal plain of the ocean.

The following can help form continental rise:

  • Mass wasting;
  • deposition from contour currents and
  • the longitudinal settling of biogenic and clastic particles

4. Abyssal Plain.

This is the real bottom of the ocean. There is a very high probability that one would find animals such as nematodes, polychaetes, etc which are all types of worms down there. The Abyssal plain is also home to molluscs,  and echinoderms.

5. Oceanic Trench

Sometimes there is a long and narrow indenture or depression along the seafloor. These are called Trenches. Trenches are sometimes formed by the boundaries between one lithospheric plate and another. The deepest trench on earth is found in the Pacific Ocean. It has been nick-named the Challenger Deep and said to be the deepest point known on earth reaching almost 11 kilometers.

6. Mid-Ocean Ridge

This is a mountain range underneath the ocean. It is formed when there is an upward push by convection currents of the mantle beneath the oceanic crust. When this happens and molten magma is ejected or created at the boundary between the plates, the result is a Mid-Oceanic Ridge.

Cheers

7 0
2 years ago
A piece of lead with a mass of 14.9 grams at a temperature of 92.5 degrees Celsius is dropped into an insulated container of wat
Vesna [10]

the specific heat of lead is

6 0
3 years ago
Read 2 more answers
What is the electron configuration of an element with atomic number 20?
VARVARA [1.3K]
1s2,2s2.2p6,3s2,3p6,3d4,4s2
8 0
3 years ago
Read 2 more answers
A sample of CaCO3 (molar mass 100. g) was reported as being 30. percent Ca. Assuming no calcium was present in any impurities, c
natka813 [3]

Answer:

Approximately 75%.

Explanation:

Look up the relative atomic mass of Ca on a modern periodic table:

  • Ca: 40.078.

There are one mole of Ca atoms in each mole of CaCO₃ formula unit.

  • The mass of one mole of CaCO₃ is the same as the molar mass of this compound: \rm 100\; g.
  • The mass of one mole of Ca atoms is (numerically) the same as the relative atomic mass of this element: \rm 40.078\; g.

Calculate the mass ratio of Ca in a pure sample of CaCO₃:

\displaystyle \frac{m(\mathrm{Ca})}{m\left(\mathrm{CaCO_3}\right)} = \frac{40.078}{100} \approx \frac{2}{5}.

Let the mass of the sample be 100 g. This sample of CaCO₃ contains 30% Ca by mass. In that 100 grams of this sample, there would be \rm 30 \% \times 100\; g = 30\; g of Ca atoms. Assuming that the impurity does not contain any Ca. In other words, all these Ca atoms belong to CaCO₃. Apply the ratio \displaystyle \frac{m(\mathrm{Ca})}{m\left(\mathrm{CaCO_3}\right)} \approx \frac{2}{5}:

\begin{aligned} m\left(\mathrm{CaCO_3}\right) &= m(\mathrm{Ca})\left/\frac{m(\mathrm{Ca})}{m\left(\mathrm{CaCO_3}\right)}\right. \cr &\approx 30\; \rm g \left/ \frac{2}{5}\right. \cr &= 75\; \rm g \end{aligned}.

In other words, by these assumptions, 100 grams of this sample would contain 75 grams of CaCO₃. The percentage mass of CaCO₃ in this sample would thus be equal to:

\displaystyle 100\%\times \frac{m\left(\mathrm{CaCO_3}\right)}{m(\text{sample})} = \frac{75}{100} = 75\%.

3 0
3 years ago
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